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Nutka1998 [239]

4 years ago

14

A DC generator is similar to an AC generator except that in

2 answers:

Brums [2.3K]4 years ago

5 0

The answer would be...B. DC generators, commutators produce direct current.

stealth61 [152]4 years ago

5 0

Answer:

B. DC generators, commutators produce direct current.

Explanation:

A generator converts mechanical energy to electrical energy. A DC generator produces DC output that is current in single direction. An AC generator produces AC output that is an alternating current.

An AC generator is similar to DC generator except that a commutator or a rectifier is required for producing DC output in DC generator.

A commutator is used mechanically to produce a direct current in a DC generator. It reverses the direction of current in every half cycle producing current in single direction.

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Answer:

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3 years ago

Physics laws of motion

expeople1 [14]

The acceleration is $0.095 m/s^2$

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:

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where:

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In this problem, we have the following forces acting on the system:

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$a=\frac{F_1-F_2}{m}=\frac{2500+(-2400)}{1050}=0.095 m/s^2$

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3 years ago

Several years from now you have graduated with an engineering/physics degree from OSU and have been hired by a nanoengineering f

spayn [35]

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3 years ago

A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m

Tatiana [17]

Answer:

Explanation:

Given

mass of each railroad is M

first railroad is moving with velocity $v_1$ and other two's with $v_2$

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where v_f is the final velocity of combined system

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$=\frac{1}{2}Mv_1^2+\frac{1}{2}2Mv_2^2$

$=\frac{1}{2}Mv_1^2+Mv_2^2$

Final Kinetic Energy

$=\frac{1}{2}3Mv_f^2=\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)$

Loss in Kinetic Energy

$=\frac{1}{2}Mv_1^2+Mv_2^2-\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)$

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7 0

4 years ago

A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r

Archy [21]

Answer:

The time taken by the rock to reach the ground is 0.569 seconds.

Explanation:

Given that,

A student throws a rock horizontally off a 5.0 m tall building, s = 5 m

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We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :

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So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers