2). If you record a wave going 4m/s and the Period of the wave was 60s, how long was the wave?

what occurs in a chemical reaction? A. Reactants are formed without chemical bonds being broken B. Reactants are formed from pro

Ann [662]

The answer is D. Products are formed from reactants by the breaking and forming of new bonds.

3 0

2 years ago

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A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their

Rom4ik [11]

Answer:

b) Nothing will happen, the sea saw will still be balanced.

Explanation:

b) Nothing will happen, the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

4 0

3 years ago

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Identify the region in the image where lighter elements, such as hydrogen or helium, are more likely to be found in a liquid or

Annette [7]

Lower in an arrangement

3 0

3 years ago

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What devices would be used to tell what would happen if you fell in a black hole

s2008m [1.1K]

Nothing ***************

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3 years ago

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2. A student drives 7.8-km trip to school and averages a speed of

Alekssandra [29.7K]

Answer:

The total time is: t=451.22 sec

The average speed is: V=34.57 m/s

Explanation:

Average speed

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

$\displaystyle V=\frac{x}{t}$

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

$\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec$

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

$\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec$

The total time is:

$t=239.26\ sec+211.96\ sec=451.22\ sec$

$\boxed{t=451.22\ sec}$

The average speed is:

$\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s$

$\boxed{\displaystyle V=34.57\ m/s}$

6 0

3 years ago