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Ne4ueva [31]
3 years ago
14

Sunlight reflected off a mirror you are holding is focused at a point 330 mm in front of the mirror.

Physics
1 answer:
lana [24]3 years ago
7 0

Answer:

Focal length of the mirror will be 660 mm          

Explanation:

We have given that sunlight is focused at a distance of 330 mm in front of mirror

So focal length f = 330 m

We have to find the radius of curvature

Radius of curvature is double the focal length

So radius of curvature = 2× focal length = 2×330 = 660 mm

So focal length of the mirror will be equal to 660 mm

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The simulation shows a game of tug-of-war. Place a blue team and a red team with same-sized people on each side of the rope. Wha
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Answer:

When same-sized team members are placed on each side of the rope, the sizes of the arrows on both sides remain the same.

Explanation:

This is the answer on Plato

6 0
3 years ago
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At what speed does a 1,248 kg compact car have the same kinetic energy as a 18,777 kg truck going 26 km/h?
notka56 [123]

The speed of car is 100.8km/h

KE =  \frac{1}{2} m(v \: truck ) {}^{2}

= 0.5 \times 18777 \times  \frac{26}{3.6} \times  \frac{26}{3.6}

= 489708.79j

=  \frac{1}{2}  \times 1248 \times( v \: car) {}^{2}

= 624v {}^{2}

so \: v {}^{2}  =  \frac{489708.7}{624}

= 784

v =  \sqrt{784}

v = 28m/s

v car= 28×3.6

=100.8km/h

Hence, the speed of the car is 100.8km/h

learn more about speed from here:

brainly.com/question/28326855

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3 0
1 year ago
You serve a volleyball with a mass of 2.5 kg. The ball leaves your hand with a speed of 23 m/s. What is the kinetic energy of th
Zarrin [17]

Answer:

661.25, I believe!

Explanation:

KE = (1/2)(2.5)(23)^2

KE=(1.25)(529)

KE= 661.25

8 0
3 years ago
50 POINTS!
zysi [14]

<h3>No:1</h3>

The object is moving with constant or uniform acceleration and in average speed

<h3>No:-2</h3>

The object is de accelerating

<h3>No:-3</h3>

The object deaccelerated and came to rest so fast.

<h3>No:-4</h3>

The object moves slowly first then accelerated.

<h3>No:-5</h3>

The object accelerated at first so fast then move with constant acceleration then again accelerated .

7 0
3 years ago
A car is running at a velocity of 50 miles/hour and the driver accelerates the car by 10miles/hour.How far the car travels from
dezoksy [38]
Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
Distance travelled S = ut + (at^2)/2
Substituting the values in the second equation of motion,
S = 50*2 + (10 * 2 *2)/2
S = 100 + 20
S = 120 miles
Therefore the distance travelled by the car in the next two hours is 120 miles
4 0
3 years ago
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