I think it’s D...not sure tho !
1. Pick a point on the top of the object and draw two incident rays traveling towards the mirror. Using a straight edge, accurately draw one ray so that it passes exactly through the focal point on the way to the mirror. Draw the second ray such that it travels exactly parallel to the principal axis.
Answer:
(a) 1294.66 m
(b) 88.44°
Explanation:
d1 = 580 m North
d2 = 530 m North east
d3 = 480 m North west
(a) Write the displacements in vector forms
![\overrightarrow{d_{1}}=580\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B1%7D%7D%3D580%5Cwidehat%7Bj%7D)
![\overrightarrow{d_{2}}=530\left ( Cos45\widehat{i}+Sin45\widehat{j} \right )](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B2%7D%7D%3D530%5Cleft%20%28%20Cos45%5Cwidehat%7Bi%7D%2BSin45%5Cwidehat%7Bj%7D%20%5Cright%20%29)
![\overrightarrow{d_{2}}=374.77\widehat{i}+374.77\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B2%7D%7D%3D374.77%5Cwidehat%7Bi%7D%2B374.77%5Cwidehat%7Bj%7D)
![\overrightarrow{d_{3}}=480\left ( - Cos45\widehat{i}+Sin45\widehat{j} \right )](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B3%7D%7D%3D480%5Cleft%20%28%20-%20Cos45%5Cwidehat%7Bi%7D%2BSin45%5Cwidehat%7Bj%7D%20%5Cright%20%29)
![\overrightarrow{d_{3}}=-339.41\widehat{i}+339.41widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd_%7B3%7D%7D%3D-339.41%5Cwidehat%7Bi%7D%2B339.41widehat%7Bj%7D)
The resultant displacement is given by
![\overrightarrow{d}\overrightarrow{d_{1}}+\overrightarrow{d_{2}}+\overrightarrow{d_{3}}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%5Coverrightarrow%7Bd_%7B1%7D%7D%2B%5Coverrightarrow%7Bd_%7B2%7D%7D%2B%5Coverrightarrow%7Bd_%7B3%7D%7D)
![\overrightarrow{d}=\left ( 374.77-339.41 \right )\widehat{i}+\left ( 580+374.77+339.41 \right )\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%3D%5Cleft%20%28%20374.77-339.41%20%5Cright%20%29%5Cwidehat%7Bi%7D%2B%5Cleft%20%28%20580%2B374.77%2B339.41%20%5Cright%20%29%5Cwidehat%7Bj%7D)
![\overrightarrow{d}=35.36\widehat{i}+1294.18\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bd%7D%3D35.36%5Cwidehat%7Bi%7D%2B1294.18%5Cwidehat%7Bj%7D)
magnitude of the displacement
![d ={\sqrt{35.36^{2}+1294.18^{2}}}=1294.66 m](https://tex.z-dn.net/?f=d%20%3D%7B%5Csqrt%7B35.36%5E%7B2%7D%2B1294.18%5E%7B2%7D%7D%7D%3D1294.66%20m)
d = 1294.66 m
(b) Let θ be the angle from + X axis direction in counter clockwise
![tan\theta =\frac{1294.18}{35.36}=36.6](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%5Cfrac%7B1294.18%7D%7B35.36%7D%3D36.6)
θ = 88.44°