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lesantik [10]
3 years ago
10

What is the momentum in Kg m/s of a 10 kg truck travelling at A) 5 m/s B) 20 cm/s C) 36 km/h?​

Physics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

A)   50 kg m/s

B)  2 kg m/s

C)  100 kg m/s

Explanation:

Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:

A)  p = m * v = 10 kg * 5 m/s = 50 kg m/s

B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)

C) the conversion from km/h to m/s is a little more involved, so we taclke it first:

since 1 km = 1000 m  and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:

36 \frac{km}{h} =36\,\frac{1000\,m}{3600\,\,s}=10\,\frac{m}{s}

Then, the momentum is:  p = m * v = 10 kg * 10 m/s = 100 kg m/s

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The process of splitting one large nucleus into
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Star A and Star B have different apparent brightnesses but identical luminosities. Star A is 10 light years away from earth and
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intensity of a star is inversely depends on the square of the distance from the star

we can say it is given as

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here we know that

\frac{I_1}{I_2} = 36 times

also we know that

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now we will have

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

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8 0
3 years ago
Zoe is shown two mystery boxes that are both 8,000cm3. Her teacher tells her that one mystery box is filled with rocks and the o
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The box of rocks will have depression which can be seen without touching the box.

Explanation:

The density of rocks is very large as compared with napkins. So, the weight of the rocks will be much more greater than that of napkins.

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X rays are used in hospital to locate in the patients bones.If the x rays of wavelength of 2×10 to the power negative nine m tra
jasenka [17]

Answer:1.5×10 to the power of 17(unit-Hertz/H)

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8 0
3 years ago
In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an
VashaNatasha [74]

Answer:

V=3.475ft^3/s=3.48ft^3/s

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})

P= 73.7*10^{3}ft.lbf/s

we have other values such h=400ft and  \gamma= 62.42lb/ft^3 (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

V=\frac{P}{\gamma h \eta_0}

Where \eta_0 is the turbine efficiency, at which is,

\eta_0 = \frac{P}{\gamma Vh}

Replacing,

V=\frac{73.7*10^{3}}{62.42*400*0.85}

V=3.475ft^3/s

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

m= 217lbm/s

6 0
3 years ago
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