What is the momentum in Kg m/s of a 10 kg truck travelling at A) 5 m/s B) 20 cm/s C) 36 km/h?
1 answer:
Answer:
A) 50 kg m/s
B) 2 kg m/s
C) 100 kg m/s
Explanation:
Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:
A) p = m * v = 10 kg * 5 m/s = 50 kg m/s
B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)
C) the conversion from km/h to m/s is a little more involved, so we taclke it first:
since 1 km = 1000 m and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:
Then, the momentum is: p = m * v = 10 kg * 10 m/s = 100 kg m/s
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Answer:
Distance: 21 yd, displacement: 15 yd, gain in the play: 12 yd
Explanation:
The distance travelled by Sam is just the sum of the length of each part of Sam's motion, regardless of the direction. Initially, Sam run from the 3 yd line to the 15 yd line, so (15-3)=12 yd. Then, he run also 9 yd to the right. Therefore, the total distance is
d = 12 + 9 = 21 yd
The displacement instead is a vector connecting the starting point with the final point of the motion. Sam run first 12 yd straight ahead and then 9 yd to the right; these two motions are perpendicular to each other, so we can find the displacement simply by using Pythagorean's theorem:
Finally, the yards gained by Sam in the play are simply given by the distance covered along the forward-backward direction only. Since Sam only run from the 3 yd line to the 15 yd line along this direction, then the gain in this play was
d = 15 - 3 = 12 yd
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75k
Explanation:
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