This bee is doing an important job! It is helping this plant reproduce. How is the bee helping the plant?
1 answer:
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Answer:
B. 17.0.
Explanation:
Hello!
In this case, considering that based on the atomic mass of the carbon atom, which means that 1 mole of carbon weights 12.01 grams, we can set up the following proportional factor to compute the moles of carbon in 200.0 grams:
Thus, the answer would be B. 17.0.
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Answer:
Explanation:
Hello,
This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:
Which accounts for an exothermic chemical reaction.
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Answer:
5.82 L
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 2.25 L
V₂ = ?
P₁ = 2.7 atm
T₁ = 12 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
At STP, Pressure = 1 atm and Temperature = 273.15 K
So,
P₂ = 1 atm
T₂ = 273.15 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 5.82 L</u>
Answer:
The final temperature of the given ideal diatomic gas: <u>T₂ = 753.6 K</u>
Explanation:
Given: Atmospheric pressure: P = 1.0 atm
Initial Volume: V₁ , Final Volume: V₂ = V₁ (1/10)
⇒ V₁ / V₂ = 10
Initial Temperature: T₁ = 300 K, Final temperature: T₂ = ? K
For a diatomic ideal gas: γ = 7/5
For an adiabatic process:
<em><u>Therefore, the final temperature of the given ideal diatomic gas</u></em><em>:</em> T₂ = 753.6 K