Ask question

Ask question

All categories

Brilliant_brown [7]

2 years ago

12

Which of the following causes clouds to form?

2 answers:

Svetllana [295]2 years ago

5 0

The answer is B because this is part of precipitation and in the process Water vapor condensing as it rises into cooler air and the clouds gets heavy from the condensation and forms clouds then the clouds form rain and the rain gets heavy and falls down.

alisha [4.7K]2 years ago

4 0

The correct answer is B. Water vapor condensing as it rises into cooler air
Hope this helps have a nice day

You might be interested in

Barry is conducting an experiment and rolls a tennis ball down a ramp. Which best describes the motion of the tennis ball? It do

yawa3891 [41]

Answer:

A. It does not exhibit projectile motion and follows a straight path down the ramp.

7 0

2 years ago

Read 2 more answers

A 60 W lightbulb is on for 24 hours. A stereo with a power of 150 W is on for 2

Helen [10]

Answer:

B) The lightbulb uses 4,104,000 J more than the stereo.

6 0

2 years ago

(physical science) could someone please help me out with this lab? if i’m being honest i did the lab but i lost all of my work :

djverab [1.8K]

Explanation:

hdhhrhhrhehhshsujwuuwuwuwwh

6 0

2 years ago

A flashing red traffic light at an intersection means

k0ka [10]

Just do what u would do if u were at a stop sign

5 0

3 years ago

A voltage V is applied to the primary coil of a step-up transformer with a 3:1 ratio of turns between its primary and secondary

Snezhnost [94]

Explanation:

Let $N_p\ and\ N_s$ are the number of turns in primary and secondary coil of the transformer such that,

$\dfrac{N_p}{N_s}=\dfrac{1}{3}$

A resistor R connected to the secondary dissipates a power $P_s=100\ W$

For a transformer, $\dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}$

$V_s=(\dfrac{N_s}{N_p})V_p$

$V_s=3V_p$ ...............(1)

The power dissipated through the secondary coil is :

$P_s=\dfrac{V_s^2}{R}$

$100\ W=\dfrac{V_s^2}{R}$

$V_p^2=\dfrac{100R}{9}$ .............(2)

Let $N_p'\ and\ N_s'$ are the new number of turns in primary and secondary coil of the transformer such that,

$\dfrac{N_p'}{N_s'}=\dfrac{1}{24}$

New voltage is :

$V_s'=(\dfrac{N_s'}{N_p'})V_p'$

$V_s'=24V_p$ ...............(3)

So, new power dissipated is $P_s'$

$P_s'=\dfrac{V_s'^2}{R}$

$P_s'=\dfrac{(24V_p)^2}{R}$

$P_s'=24^2\times \dfrac{(V_p)^2}{R}$

$P_s'=24^2\times \dfrac{(\dfrac{100R}{9})}{R}$

$P_s'=6400\ Watts$

So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.

3 0

3 years ago