<span>The maxima of an equation can be obtained by taking the 1st
derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.
Taking the 1st derivative of
the equation y=(kn)/(9+n^2) :<span>
</span>
By using the quotient
rule the form of the equation is:<span>
y = g(n) / h(n)
where:</span>
g(n) = kn --->
g'(n) = k
<span>
<span>h(n) = 9 + n^2 ---> h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 +
n^2)^2
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2
dy/dn = (9k - kn^2) / (9 + n^2)^2
dy/dn = k(9 - n^2) / (9 + n^2)^2
<span>Equate dy/dn = 0, then solve for n
k(9 - n^2) / (9 + n^2)^2 = 0
k(9 - n^2) = 0
9 - n^2 = 0
n^2 = 9
n = sqrt(9)
n = 3
<span>Answer: The nitrogen
level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>
Answer:
.004 Hz
Explanation:
Frequeny is cycles per second. An oscillation is 1 cycle
F=cycles/sec
4/100
=0.004Hz (Hz- Hertz=1 cycle/sec)
Answer:
1125.66956 N
Explanation:
m = Mass of stunt performer
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity of the swing = 7 m/s
T = Tension
r = Radius of the swing = Length of vine = 11.5 m
From the free body diagram

The minimum tension force the vine must be able to support without breaking is 1125.66956 N
Answer:
55 ft/s
Explanation:
A₁ = Area of rectangular cross-section at input side = 1.5 x 11 = 16.5 ft²
A₂ = Area of rectangular cross-section at far end = 1.5 x 6 = 9 ft²
v₁ = speed of water at the input side of channel = 30 ft/s
v₂ = speed of water at the input side of channel = ?
Using equation of continuity
A₁ v₁ = A₂ v₂
(16.5) (30) = (9) v₂
v₂ = 55 ft/s