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3 years ago

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A glider of mass m1 on a frictionless horizontal track is connected to an object of mass m2 by a massless string. The glider acc

elerates to the right, the object accelerates downward, and the string rotates the pulley. The pulley has a moment of inertia I. What is the relationship among T1 (the tension in the horizontal part of the string), T2 (the tension in the vertical part of the string), and the weight m2g of the object

1 answer:

inysia [295]3 years ago

5 0

Answer:

m2g -> T2 -> T1

Explanation:

m2g -> T2 -> T1

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Please show steps as to how to solve this problem <br> Thank you!

bezimeni [28]

Explanation:

Let x = distance of $F_1$ from the fulcrum and let's assume that the counterclockwise direction is positive. In order to attain equilibrium, the net torque $\tau_{net}$ about the fulcrum is zero:

$\tau_{net} = -F_1x + F_2d_2 = 0$

$-m_1gx + m_2gd_2 = 0$

$m_1x = m_2d_2$

Solving for <em>x</em>,

$x = \dfrac{m_2}{m_1}d_2$

$\:\:\:\:=\left(\dfrac{105.7\:\text{g}}{65.7\:\text{g}} \right)(13.8\:\text{cm}) = 22.2\:\text{cm}$

4 0

3 years ago

The electric field in the region between the plates of a parallel plate capacitor has a magnitude of 6.3 105 V/m. If the plate s

xz_007 [3.2K]

Answer:

3.528×10² V.

Explanation:

potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,

V = kq/r..................... Equation 1

And

E = kq/r² .................. Equation 2

Comparing equation 1 and equation 2,

V = E×r............................. Equation 3

Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.

Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.

Substitute into equation 3,

V = 6.3×10⁵×0.00056

V = 3.528×10² V.

Hence the potential difference of the plate = 3.528×10² V.

4 0

3 years ago

Jack (mass 59.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. He collides with Jill (mass 47.0 k

Phantasy [73]

Answer:

Part(A): The magnitude of Jill's final velocity is $\bf{6.59~m/s}$ .

Part(B): The direction is $\bf{42.7^{0}}$ south to east.

Explanation:

Given:

Mass of Jack, $m_{1} = 59.0~Kg$

Mass of Jill, $m_{2} = 47..0~Kg$

Initial velocity of Jack, $v_{1i} = 8.00~m/s$

Initial velocity of Jill, $v_{2i} = 0$

Final velocity of Jack, $v_{1f} 5.00~m/s$

The final angle made by Jack after collision, $\alpha = 34.0^{0}$

Consider that the final velocity of Jill be $v_{2f}$ and it makes an angle of $\beta$ with respect to east, as shown in the figure.

Conservation of momentum of the system along east direction is given by

$~~~~&& m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} \cos \alpha + m_{2}v_{2f}^{x}\\&or,& v_{2f}^{x} = \dfrac{m_{1}(v_{1i} - v_{1f} \cos \alpha)}{m_{2}}$

where, $v_{2f}^{x}$ is the component of Jill's final velocity along east. The direction of this component will be along east.

Substituting the value, we have

$v_{2f}^{x} &=& \dfrac{(59.0~Kg)(8.00~m/s - 5.00 \cos 34.0^{0}~m/s)}{47.0~Kg}\\~~~~~&=& 4.84~m/s$

Conservation of momentum of the system along north direction is given by

$~~~~&& v_{2f}^{y} + v_{1f} \sin \alpha = 0\\&or,& v_{2f}^{y} = - v_{1f} \sin \alpha = (8.00~m/s) \sin 34^{0} = 4.47~m/s$

where, $v_{2f}^{y}$ is the component of Jill's final velocity along north. The direction of this component will be along the opposite to north.

Part(A):

The magnitude of the final velocity of Jill is given by

$v_{2f} &=& \sqrt{(v_{2f}^{x})^{2} + (v_{2f}^{y})^{2}}\\~~~~~&=& 6.59~m/s$

Part(B):

The direction is given by

$\beta &=& \tan^{-1}(\dfrac{4.47~m/s}{4.84~m/s})\\~~~~&=& 42.7^{0}$

4 0

3 years ago

The lineage of pea plants produced round seeds for four generations. The plants that fertilized these pea plants also produced r

frutty [35]

Answer:

When two heter0zyg0us individuals are crossed -simple d0minant inheritance-, or a heter0zyg0us individual is crossed with a h0m0zyg0us recessive one, they can produce h0m0zyg0us recessive subjects among the progeny. Heter0zyg0us individuals among the fourth generation got crossed with another plant (h0m0zyg0us recessive or heter0zyg0us) and produced two h0m0zyg0us recessive plants expressing wrinkle seeds.

---------------------------

The first step is to understand the given information. So,

The first four generations produced round seeds

Plants that fertilized these plants also produced round seeds (see generation II)

Among the fifth generation there are two plants with wrinkled seeds

Let us assume that a diallelic gene determines the shape of seeds.

D0minant allele R codes for round seeds

Recessive allele r codes for wrinkle seeds

Now, let us analyze the pedigree. According to the information provided here, we can tell that

black figures represent h0m0zyg0us d0minant individuals,

grey figures represent heter0zyg0us individuals

empty figures represent h0m0zyg0us recessive individuals

Remember that Generations are represented with roman numbers.

We will name the plants with numbers from 1 to 26.

According to the information in the statement and the information in the pedigree, we can say that grey individuals from the fourth generation are heter0zyg0us expressing round seeds. They can produce wrinkle seeds, if they are fertilized by another heter0zyg0us plant or a h0m0zygous recessive one.

Option 1:

Two heter0zyg0us plants are crossed, and their offspring have wrinkled seeds.

Option 2:

One heter0zyg0us plant is crossed with a h0m0zyg0us recessive one, and their offspring have wrinkled seeds. Let us see the cross

Look at the attached files for a better understanding

---------------------------------

Related link: brainly.com/question/2952835?referrer=searchResults

Explanation:

3 0

2 years ago

Based on the graph, how would you describe the motion of the object?

Rashid [163]

<u>Answer:</u>

Given graph showing the relation between Velocity and time. And it is clear from the graph that the <em>"Velocity is constant with respect to the time".</em>

The velocity of the graph is a function of time is equal to the acceleration.
Horizontal slope (Zero slope) in the graph implies<em> zero acceleration</em>

<em> </em><em>Therefore the given graph gives the a</em><em>cceleration is zero,</em><em> Also We calculate the acceleration from the mathematical relations results in </em><em>Zero acceleration.</em>

3 0

3 years ago