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Stolb23 [73]
4 years ago
7

Which statement is TRUE about 300 ? A) It lies between 14 and 15 on a number line. B) It lies between 15 and 16 on a number line

. Eliminate C) It lies between 16 and 17 on a number line. D) It lies between 17 and 18 on the number line.
Mathematics
2 answers:
musickatia [10]4 years ago
6 0

we need a picture of a number line lol

chubhunter [2.5K]4 years ago
3 0

Answer:

the answer is D between 17 and 18

Step-by-step explanation:

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The initial number of people that are sick with the flu is 36 and growing at a rate of 8% every day. How many people will be sic
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This is an example of an exponential growth problem.

 The formula for this is : y = x(1+r)^t
y = final amount
x = starting amount = 36
r = rate = 8% = 0.08
t = time = 11 days

y = 36(1+0.08)^11

y = 36 (1.08)^11
y = 36*2.3316389
y = 83.94 = 84 people


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87

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Which quadratic equation has a vertex at (4, 2)?
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3 years ago
A study showed that the ratio of the number of people who get their news from social media to the number of people who their new
Kitty [74]

Answer: 240 people get the news from social media

Step-by-step explanation:

The ratio of the number of people who get their news from social media to the number of people who their news elsewhere is 3:7

Total ratio is the sum of the proportion of those that get their news from social media and those that got their news elsewhere.

It becomes 3+7 = 10

Total number of people in the town is 800

To determine the number of people that got their news from social media, we will divide the proportion of those that get their news from social media by the total ratio and multiply by the total number of people in the town. It becomes

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6 0
3 years ago
What is an equation of the line that passes through the point (-6, -7) and is
Alexandra [31]

Answer:

Step-by-step explanation:

Product of slope of perpendicular lines = -1

6x + 5y = 30

Write this equation in y = mx + b  form

        5y = -6x + 30

          y = \frac{-6}{5}x+\frac{30}{5}

          y=\frac{-6}{5}x + 6

Slope of this line m₁ = -6/5

m₁ * m₂ = -1

      m₂ = -1÷m₁ = -1 * \frac{5}{-6}  

m_{2}=\frac{5}{6}     & (-6 , -7)

Equation of the required line: y - y₁ = m (x - x₁)

y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2

8 0
3 years ago
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