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Bezzdna [24]
3 years ago
13

Pleaaaaase hellllp asaaaap

Chemistry
1 answer:
rewona [7]3 years ago
8 0

Answer:

solve example number 2 ....

Explanation:

solve examole number 2 .....

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Because both tin and carbon are members of Group 4A(14), they form structurally similar compounds. However, tin exhibits a great
Nitella [24]

Answer:

See Explanation

Explanation:

Elements in group fourteen are mostly known to form compounds in which there are four electron domains leading to a tetrahedral electron domain geometry.

However, the presence of lone pairs affects the shape of the molecule. SnCl3− has four electron domains, three of them are bond pairs while one is a lone pair. The shape of the molecule is based on a tetrahedron, however the observed geometry is trigonal pyramidal due to the presence of the lone pair. Its bond angle is now less than the predicted 109 degrees.

5 0
3 years ago
After our solar system began to form, dust and gas combined into small bodies that formed the planets. What are these small bodi
saul85 [17]

Answer:

Planetesimal

Explanation:

According to Nebular Theory, the Solar system was formed from the Solar Nebula about 4.6 billion years ago. Nebula is a molecular cloud composed of dust and gases. Majority of the mass accreted to form a core which gradually formed the Sun. The remaining mass of the disk surrounding the core accreted into small bodies known as Planetesimal which formed the planets.

7 0
4 years ago
Read 2 more answers
A speed-time graph shows a line sloping downward. How was the speed changing?
Mice21 [21]
It means it has a constant deceleration
3 0
3 years ago
Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr
pantera1 [17]

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

6 0
3 years ago
Calculate the percent composition by mass of each element in Al(OH)3. Use at least three significant figures.
motikmotik

Answer:

nope nope nope nope nope nope nope nope

7 0
3 years ago
Read 2 more answers
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