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dlinn [17]
3 years ago
7

What is the mobile phase in chromatography

Chemistry
1 answer:
Sonbull [250]3 years ago
6 0
Mobile phase is the liquid or organic solvent present in the developing tank or beaker by Ayesha zulfiqar

(Hoped that helped)
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Which of the following could be true of two species that have a competitve ralationship in the same ecosystems Help me out pleas
ankoles [38]
The answer is b. as a whole, the species is mutually beneficial to carry on each others traits and exist in the same ecosystem.
6 0
3 years ago
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Under conditions of "feasting", the body favors oxidation/utilization of which source for energy production
mezya [45]
During feasting, there is an increase in the supply of carbohydrates, fats and proteins in the body. Since these macronutrients are in excess, carbohydrates and proteins are utilized or oxidized as a source for energy production. On the otherhand, fats are accumulated as the rate of oxidation of this source does not increase during feasting. 


4 0
3 years ago
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A decomposition occurs when you open a can or bottle of soda. Carbonic acid. H.CO, is in carbonated beverages. It
Rina8888 [55]

Answer:

H₂CO₃→H₂O + CO₂

Exphlanation:

Soda is carbonated water. It contains carbon dioxide dissolved in water , which is carbonic acid. On opening the soda, the carbonic acid undergoes the reverse reaction and releases carbon dioxide in the air . The soda is thus left with just water and loses it's fizz.

3 0
3 years ago
How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?
zaharov [31]

Answer:

m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2

Best regards!

7 0
3 years ago
In photosynthesis-
In-s [12.5K]

Answer:

A.

Explanation:

7 0
3 years ago
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