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Gemiola [76]
2 years ago
8

Given a 9.7 pF air-filled capacitor, you are asked to convert it to a capacitor that can store up to 7.7 µJ with a maximum poten

tial difference of 550 V. What must be the dielectric constant of the material that you should you use to fill the gap in the air capacitor if you do not allow for a margin of error?
Physics
1 answer:
salantis [7]2 years ago
3 0

Answer:

ε = 5.24

Explanation:

In order to find the values of the dielectric constant of some material, which allows one to store an energy  of 7.7µJ, you use the following formula:

E=\frac{1}{2}CV^2       (1)

C: capacitance  = 9.7 pF

V: potential difference on the capacitor = 550 V

E: energy storage on the capacitor

Furthermore, you take into account that, when a dielectric material is included in the capacitor, its capacitance is modified as follow:

C'=\epsilon C

To find the value of ε, you use the equation (1), but for C = C'.

E=\frac{1}{2}C'V^2=\frac{1}{2}\epsilon CV^2      (2)

Then, you solve for ε in the previous equation:

\epsilon=\frac{2E}{CV^2}=\frac{2(7.7*10^{-6}J)}{(9.7*10^{-12}F)(550V)^2}\\\\\epsilon=5.24

The dielectric constant of the material required is 5.24

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lbvjy [14]

Answer:

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Explanation:

The free body diagram of the question is shown on the first uploaded image From the question we are told that

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          The mass tied between the two cloth line is  m = 3Kg

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Now the sum of the forces on the y-axis is zero assuming  that the whole system is at equilibrium

       And this can be mathematically represented as

                             \sum F_y = 0

 To obtain \theta we apply SOHCAHTOH Rule

 So    Tan \theta = \frac{opp}{adj}

          \theta = tan^{-1} [\frac{opp}{adj} ]

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=>  \  \ \ \ \ \ \ \ 2T sin\theta -mg =0

=>  \  \ \ \ \ \ \ \ T =\frac{mg}{2 sin\theta}

=>  \  \ \ \ \ \ \ \ T = \frac{3 * 9.8 }{2 sin \theta }

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Answer:

See below

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