The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams.
Explanation:
Balance equation for the reaction:
2NO + ⇒ 2N
Data given:
mass of nitrogen produced = 20 gram
mass of oxygen = 29.8 litres or 29800 grams
0xygen is the limiting reagent so,
number of moles of oxygen: (atomic mass of 1 mole 32 grams/mole
number of moles =
putting the values in the equation:
=
= 931.5 moles
1 mole of oxygen reacts to give 2 moles of NO2
931.5 moles of oxygen will give x moles
=
1862.5 moles of NO2 produced
in grams
mass = number of moles x atomic mass
mass = 1862.5 x 46.00
= 85675 grams
The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams as said in question.
Answer:
27 min
Explanation:
By the Michaelis-Menten Kinetics Model, the initial velocity of the enzymatic reaction is given by:
where vmax is the maximum velocity, [S] is the substrate concentration and Km is the equilibrium constant. The maximum velocity is directly proportional to the enzyme concentration.
So, for 12μmol of the product formed in 9 min, the velocity is also:
v0 = 12/9 = 1.33 μmol/min
For [S] 1,000 times higher then Km, Km can be unconsidered in the equation, so:
v0 = vmax
vmax = 1.33 μmol/min
If the enzyme concentration decreases by three, the maximum velocity will also decrease by three, so it will be: 0.443μmol/min. Km continues the same, and [S] will be multiplied by 2, so Km can still be unconsidered. So:
v0 = vmax
v0 = 0.443 μmol/min
Then,
0.443 = 12/t
t = 12/0.443
t = 27 min
First, you need to be given the gram formula mass of this molecular or related conditions that can calculate this. Then you need the empirical formula and calculate the gram formula mass of empirical formula. Then use them to get the ratio. Finally you can get the molecular formula.