Answer:
11.7 m
Explanation:
I assume north is the y direction and x is the east direction, so Δx refers to the displacement in the east direction.
First, find the time it takes for the velocity to change from directly north to directly east.
Given (in the y direction):
v₀ = 2.88 m/s
v = 0 m/s
a = 0.350 m/s² sin(-52.0°) = -0.276 m/s²
Find: t
v = at + v₀
(0 m/s) = (-0.276 m/s²) t + (2.88 m/s)
t = 10.4 s
Given (in the x direction):
v₀ = 0 m/s
a = 0.350 m/s² cos(-52.0°) = 0.215 m/s²
t = 10.4 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10.4 s) + ½ (0.215 m/s²) (10.4 s)²
Δx = 11.7 m
The weight of the meterstick is:

and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance

from the pivot.
The torque generated by the weight of the meterstick around the pivot is:

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:

from which we find the value of d2:

So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
So, the initial altitude of the parachuter is approximately <u>(C). 123 m</u>.
<h2>Introduction</h2>
Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the following equations apply:
<h3>The equation for calculating the height (h)</h3>

<h3>The equation for calculating the time (s)</h3>

<h3>The equation for calculating the velocity (v)</h3>

With the following condition :
- t = interval of the time (s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
- v = velocity (m/s)
<h2>Problem Solving</h2>
We know that :
- t = interval of the time = 5 s
- g = acceleration of the gravity = 9.81 m/s²
What was asked :
- h = height or displacement at vertical line = ... m
Step by Step :




<h3>Conclusion</h3>
So, the initial altitude of the parachuter is approximately 123 m (C.)
<h3>See More</h3>
Answer:
From smallest ratio to the largest ratio:
Coasting Universe - Critical Universe - Recollapsing Universe(From left to right)
Explanation:
The coasting universe is one that expands at a constant rate given by the Hubble constant throughout all of cosmic time. It has a ratio of actual density to critical density that is less than 1
The critical universe is one that is at balance with no expansion .I.e. the actual density and the critical density are equal, which makes the ratio of actual density to critical density to be equal to 1
Recollapsing Universe: The expansion of the universe reverses in the future and the universe eventually recollapses. The recollapsing universe has the ratio of the actual density to the critical density to be greater than 1