All categories

3 years ago

How much force is required to lift a rock a vertical distance of 8 m if 80 j of work were done

Chemistry

2 answers:

kramer3 years ago

6 0

Answer: 10N

Explanation: W = F x d

W = 80J

d = 8m

F =?

w = F x d

80 = F x 8

F = 80/8

F = 10N

NikAS [45]3 years ago

5 0

Answer:-

Try this formula:

W= Fd

F = W by d

Explanation:-

(Note: A newton-meter is the same thing as a joule, so the units for work are the same as those for energy – joules).

You might be interested in

During a lab experiment, students are supposed to add small pieces of magnesium, aluminum, and calcium metal to concentrated hyd

ser-zykov [4K]

Hydrogen gas is highly flammable.

5 0

3 years ago

Read 2 more answers

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

Answer: The concentration of $NH_3$ required will be 0.285 M.

Explanation:

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

3 years ago

which of the following is a balanced chemical equation for the reaction of magnesium with nitrogen gas to form magnesium nitride

ioda

So the unbalanced equation would be Mg + N^2 --> Mg^3N^2

Which means the balanced equation would be 3Mg + N^2 --> Mg^3N^2

This is balance the equation out since you now has 3 magnesium and 2 nitrogen on the left side, and 3 magnesium on 2 nitrogen on the right. Double check my work though, it's been awhile.

8 0

3 years ago

Add groups to complete polyvinyl alcohol, formed by the polymerization of the following monomer. If a carbon atom contains only

e-lub [12.9K]

Answer:

The resulting structure is:

R-CH-CH2 (OH)-CH-CH2(OH)-CH-CH2(OH)-CH-...

Explanation:

It can be said that vinyl alcohol cannot be polymerized by addition polymerization, since a very unstable radical would be formed, which is not possible. Generally, it is formed by polymerization and subsequent hydrolysis of the vinyl polyacetate. According to the exercise, the structure that results with its four units can be seen that the hydroxyl groups are found in the methylene carbons

8 0

4 years ago

A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure

GenaCL600 [577]

Answer:

$P_A=4.20atm\\\\P_B=17.1atm$

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

$PV=nRT$

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

$P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm$

Best regards!

8 0

3 years ago