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Arisa [49]
3 years ago
11

What is the correct chemical equation for the reaction between methane and oxygen to produce carbon dioxide and water?

Chemistry
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

The answer to your question is:   CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

Explanation:

Methane = CH₄

Oxygen = O

Carbon dioxide = CO₂

Water = H₂O

                      CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

        This is the balanced equation

                 

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The nervous system involves actions that control
NeTakaya

Answer:

The peripheral nervous system can be further divided into the autonomic system, which regulates involuntary actions, and the somatic system, which controls voluntary actions.

Explanation:

mark as brainly plz and thanks

4 0
2 years ago
Read 2 more answers
What is the formula for tetrabromine decafluoride
Lyrx [107]

Answer:

Br_{4}F_{10}

The prefix "Tetra" implies 4 Bromine atoms. The prefix "Deca" implies 10 fluorine atoms.

4 0
3 years ago
2 UNIS<br> Which of the following interactions is not a type of intermolecular force?
natima [27]

Answer:

Covalent Bonds

Explanation:

7 0
3 years ago
While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

5 0
3 years ago
Predict the direction in which the equilibrium will lie for the reactionC6H5COO- + HF C6H5COOH + F-.Ka(C6H5COOH) = 6.5 x 10-5; K
Llana [10]

Answer:

Equilibrium will lie to the right.

Explanation:

K_{a}(HF)> K_{a}(C_{6}H_{5}COOH)

That means HF is stronger acid than C_{6}H_{5}COOH.

Alternatively, it can be said that C_{6}H_{5}COO^{-} is a stronger base than F^{-}.

Therefore HF readily gives proton to C_{6}H_{5}COO^{-} to form C_{6}H_{5}COOH and F^{-} than the reverse reaction.

So, the equilibrium will lie more towards the right i.e. towards formation of C_{6}H_{5}COOH and F^{-}.

7 0
2 years ago
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