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3 years ago

Which of the following elements could be transmutated into silver by bombardment with a positron?

Chemistry

1 answer:

Elena L [17]3 years ago

6 0

Answer:

I think it's gold but I'm not sure, sorry

Explanation:

good luck tho :)

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The normal boiling point of mercury (Hg) is 356.7 °C. What is the vapor pressure of mercury at 333 °C in atm? (∆Hvap = 58.51 kJ/

grigory [225]

Answer:

Here you can use the Clausis Clayperon equation: ln P1/P2=-Ea/R-(1/T1 - 1/T2)

where P1 is the pressure at standard condition: 760 mm Hg

P2 is the variable we need to solve

Ea is the activation energy, which in this case is delta H vaporisation: 56.9 kJ/mol

R is the gas constant 8.314 J/mol or 8.314 J/mol /1000 to convert to kJ

T1 is the normal boiling point 356.7 C, but converted to Kelvin: 629.85K

T2 is room temperature 25 C, but converted to Kelvin: 298.15 K

Once you plug everything in, you should get 4.29*10^-3 mmHg

Explanation:

8 0

3 years ago

How many atoms of carbon are present in a molecule of : Fructose and galactose

nasty-shy [4]

In Fructose, there are 4 carbon atoms. Fructose is a 5 atom molecule, and one of these is oxygen, therefore, the other 4 are carbon.
In Galactose, there are 6 carbon atoms.
Hope this helps :)

6 0

4 years ago

Read 2 more answers

What is kinetix energy

posledela

Answer:

Kinetic energy is the energy developed in a body due to of its motion.It is denoted by KE

and given by,KE=

$\frac{1}{2} m {v}^{2}$

It's SI unit is J.

5 0

3 years ago

Please help, its urgent.

san4es73 [151]

Answer:

Mass of excess reactant left = 179.6 g

Limiting reactant = nitrogen

Mass of ammonia formed = 200.6 g

Explanation:

Given data:

Mass of nitrogen = 165.0 g

Mass of hydrogen = 215.0 g

Limiting reactant = ?

Mass of ammonia formed = ?

Mass of excess reactant left = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 165.0 g/ 28 g/mol

Number of moles = 5.9 mol

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 215.0 g/ 2 g/mol

Number of moles = 107.5 mol

Now we will compare the moles of ammonia with both reactant.

H₂ : NH₃

3 : 2

107.5 : 2/3×107.5 = 71.7 mol

N₂ : NH₃

1 : 2

5.9 : 2/1×5.9 = 11.8 mol

Less number of moles of ammonia are formed by the nitrogen it will act as limiting reactant.

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 11.8 mol × 17 g/mol

Mass = 200.6 g

Mass of hydrogen left:

We will compare the moles of hydrogen and nitrogen.

N₂ : H₂

1 : 3

5.9 : 3/1×5.9 = 17.7 mol

Out of 107.5 moles 17.7 moles of hydrogen react with nitrogen.

Number of moles left unreacted = 107.5 - 17.7 mol = 89.8 mol

Mass of hydrogen left:

Mass = number of moles × molar mass

Mass = 89.8 mol × 2 g/mol

Mass = 179.6 g

5 0

3 years ago

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the

Anni [7]

Answer:

A) 0.801

Explanation:

The reaction that takes place is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate the H₂SO₄ moles that reacted:

0.355 M * 28.2 mL = 10.011 mmol H₂SO₄

Now we convert H₂SO₄ moles to NaOH moles:

10.011 mmol H₂SO₄ * $\frac{2mmolNaOH}{1mmolH_2SO_4}$ = 20.022 mmol NaOH

Finally we calculate the molarity of the NaOH solution:

20.022 mmol NaOH / 25.0 mL = 0.801 M

So the answer is option A.

3 0

3 years ago