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Nataly [62]
3 years ago
11

On my science test, there is a bonus question that I want to get right. Why would it be a bad idea to skydive on the moon? Hint:

It has nothing to do with gravity. Please get back to me about it.
Physics
1 answer:
eduard3 years ago
7 0

Answer:

Because there is no air resistance

Explanation:

When an object falls on Earth, there are essentially two forces acting on it:

- The force of gravity, downward, equal to the weight of the object:

W=mg

where m is the mass and g the acceleration due to gravity

- The air resistance, F, which acts upward, and whose magnitude is generally proportional to v, the speed of the object

When the object starts its fall, its initial speed is zero: v = 0, so the air resistance is also zero: F=0, and the object accelerates downward due to gravity.

However, as it accelerates downward, its speed increases, and so does the air resistance F. However, F is upward, opposite to the direction of motion, therefore it reduces the net acceleration of the object; at a certain point, the magnitude of the air resistance will become equal to the weight, so that

mg = F

and at that point, the net acceleration of the object will become zero: this means that the object will continue its fall at a constant velocity, called terminal velocity.

On the Moon instead, there is no air resistance: this means that for an object falling down, the speed keeps increasing due to the effect of gravity, and it will never reach a terminal value: therefore, the final velocity at the impact will be much higher than on the Earth, if we assume the two objects have been dropped from a very high altitude from the surface.

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A current exists whenever electric charges move. If ΔQ is the net charge that passes through a surface during a time period Δt,
jeka57 [31]

Answer:

It represents the change in charge Q from time t = a to t = b

Explanation:

As given in the question the current is defined as the derivative of charge.

                                  I(t) = dQ(t)/dt ..... (i)

But if we take the inegral of the equation (i) for the time interval  from t=a to

t =b we get

                                   Q =∫_a^b▒〖I(t)  〗 dt

which shows the change in charge Q from time t = a to t = b. Form here we can say that, change in charge is defiend as the integral of current for specific interval of time.

5 0
3 years ago
O'Malley is riding on a bus which is moving at 10 m/s, and he throws a ball which he observes to be moving at 10 m/s relative to
Vikki [24]

Answer:

<em>20 m/s in the same direction of the bus.</em>

Explanation:

<u>Relative Motion </u>

Objects movement is always related to some reference. If you are moving at a constant speed, all the objects moving with you seem to be at rest from your reference, but they are moving at the same speed as you by an external observer.

If we are riding on a bus at 10 m/s and throw a ball which we see moving at 10 m/s in our same direction, then an external observer (called Ophelia) will see the ball moving at our speed plus the relative speed with respect to us, that is, at 20 m/s in the same direction of the bus.

3 0
3 years ago
At a certain instant, the speedometer of the car indicates 80 km/h.
Scorpion4ik [409]

Answer:

  • <em>It</em><em> </em><em>tells</em><em> </em><em>the</em><em> </em><em>speed</em><em> </em><em>of</em><em> </em><em>car</em><em>.</em><em> </em><em>At</em><em> </em><em>this</em><em> </em><em>time</em><em> </em><em>the</em><em> </em><em>speed</em><em> </em><em>of</em><em> </em><em>car</em><em> </em><em>is</em><em> </em><em>8</em><em>0</em><em>k</em><em>m</em><em>/</em><em>h</em><em> </em><em>,</em><em> </em><em>means</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>car</em><em> </em><em>runs</em><em> </em><em>constantly</em><em> </em><em>at</em><em> </em><em>this</em><em> </em><em>speed</em><em> </em><em>then</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>cover</em><em> </em><em>8</em><em>0</em><em> </em><em>kilometres</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>hour</em><em>.</em><em> </em>

<em>.</em><em> </em>

<em>.</em><em> </em>

<em>.</em>

{\bold{\red{HOPE\:IT\:HELPS!}}}

\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}

4 0
2 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
Paul [167]
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6 0
4 years ago
Read 2 more answers
You travel 23 meters north in 16 seconds, 5 meters south in 4 seconds, and 16 meters north in 18 seconds. Calculate your total d
dolphi86 [110]

Answer:

d: 44m

Δd:34  

Explanation:

d: 23+5+16= 44m

Δd: 23-5+16= 34m

4 0
3 years ago
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