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mr_godi [17]
3 years ago
13

Water, carbon, and nitrogen move through living and nonliving things on Earth through processes known as _____. A. transformatio

ns B. energy C. cycles
Chemistry
2 answers:
skelet666 [1.2K]3 years ago
6 0
Hey there
_____________
The correct answer is:
Water, carbon, and nitrogen move through living and nonliving things on Earth through processes known as C. cycles .

________________
Hope this helps you
otez555 [7]3 years ago
5 0

Water, carbon and nitrogen are transferred from one part to other of earth (both living and non living part) in different forms and reach to the starting point again.

This is a cyclic process and thus known as "cycles"

For example :

Carbon of carbon dixoide is being converted to carbohydrates by plants through photosynthesis. this is being eaten by consumers and then they digest it and release back carbon dixoide agin to atmosphere. so in this way there are other parts of carbon cycle also.

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Digestion is the process of breaking down food into substances that the can use. Which of the following is a physical change tha
Yuri [45]
C - Enzymes help break down carbohydrates.
8 0
3 years ago
Read 2 more answers
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
1. If you have 5g of pennies how many dozen pennies do you have?
likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

Therefore,

1.3075 gross = 1.3075 gross × 12 dozen / 1 gross

1.3075 gross = 15.69 dozen

Thus, 5 g of penny is equivalent to 15.69 dozen

4 0
3 years ago
Which substances are most likely acids? Check all that apply. CH4, HI, NH3, HNO3, NaCI
rosijanka [135]
Answer is: CH4 and NaCI hope this helps you
5 0
3 years ago
Give three example of univalent element​
Aloiza [94]

Answer:

Hydrogen and Chlorine

Explanation:

They are both an example in univalent atoms, because of their nature to form only one single bond.

I wasn't able to find another example, hope it helped! :)

4 0
2 years ago
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