1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nata [24]
4 years ago
5

Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h​

Physics
1 answer:
ELEN [110]4 years ago
5 0

Answer:

1848.15J

Explanation:

KE =1/2 mv^2

Mass = 60kg, velocity =40km/h =11.11m/s

Hence

KE =30 x(11.1)^2 /2 = 1848.15J

You might be interested in
A car is traveling at the bottom of a 9.00-meter-radius circular hill with a constant speed v. The moment the car is at the bott
Rina8888 [55]

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

3 0
3 years ago
momentum A proton interacts electrically with a neutral HCl molecule located at the origin. At a certain time t, the proton’s po
arlik [135]

Answer:

\ m/s

Explanation:

F = Force =

m = Mass of proton = 1.7\times 10^{-27\ kg

t = Time taken = 2\times 10^{-14}\ s

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{}{1.7\times 10^{-27}}\\\Rightarrow a=\ m/s^2

v=u+at\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\times 2\times 10^{-14}\\\Rightarrow v=+\\\Rightarrow v=\ m/s

The velocity of the proton is \ m/s

6 0
4 years ago
Which object has a volume greater than the volume of a pencil? *
Bad White [126]

Answer:

A.

Explanation:

3 0
3 years ago
Read 2 more answers
The dry adiabatic rate of change for unsaturated air is 10°c/1000 m. what does this mean
brilliants [131]
Adiabatic rate is used to describe the change in temperature as a result of the rising or the sinking of an air parcel.

Knowing that the dry adiabatic rate of change for unsaturated air is 10°C/1000 m means that the temperature of the unsaturated air parcel would increase (get warmer) as the air parcel sinks and will decrease (get cooler) as the air parcel rises.

Hope this helps :)
3 0
4 years ago
Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9×1022k
Taya2010 [7]

Answer:g=1.97 m/s^2

Explanation:

Given

mass of Jupiter is M=4.9\times 10^{22} kg

Density of Jupiter is same as Earth

density\ of\ Earth=density\ of\ Jupiter=5510 kg/m^3

mass=volume\times density

considering Jupiter to be sphere of radius r

M=\frac{4}{3}\times \pi r^3\times \rho

r^3=\frac{3M}{\rho \times 4\pi}

r^3=\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi}

r=(\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi})^{\frac{1}{3}}

r=1.28\times 10^6 m

acceleration due to gravity is given by

g=\frac{GM}{r^2}

g=\frac{6.67\times 10^{-11}\times 4.9\times 10^{22}}{(1.28\times 10^6)^2}

g=1.97 m/s^2

3 0
4 years ago
Other questions:
  • With regard to the pH scale, a solution with a pH
    11·1 answer
  • Which of the following phrases defines the angle of refraction?
    11·1 answer
  • 2. This reaction has reached equilibrium at 40.0 oC, and the total pressure is measured to be 0.363 atm. What is the equilibrium
    6·1 answer
  • Which method will provide the most emotional support in a new exercise program?
    14·1 answer
  • Four monitoring wells have been placed around a leaking underground storage tank. The wells are located at the corners of a 1-ha
    5·1 answer
  • 39
    12·1 answer
  • How does the conservation of energy effect our lives?
    11·1 answer
  • The radios of the moon is aproximately 1,350,000m)
    13·1 answer
  • Physicists call any change in energy an impulse true or false?
    10·1 answer
  • The planets that orbit the sun are large enough that their gravity produces a<br> ________ shape.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!