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4 years ago

Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h

Physics

1 answer:

ELEN [110]4 years ago

5 0

Answer:

1848.15J

Explanation:

KE =1/2 mv^2

Mass = 60kg, velocity =40km/h =11.11m/s

Hence

KE =30 x(11.1)^2 /2 = 1848.15J

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3 years ago

Read 2 more answers

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Answer:

Part a)

v = 16.52 m/s

Part b)

v = 7.47 m/s

Explanation:

Part a)

(a) when the large-mass object is the one moving initially

So here we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

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so here we can say

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Part b)

(b) when the small-mass object is the one moving initially

here also we can use momentum conservation as the net force on the system of two masses will be zero

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Again this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

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4 years ago

When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose anot

gayaneshka [121]

Answer:

The value is $E = 1.35 *10^{14} \ J$

Explanation:

From the question we are told that

The mass of matter converted to energy on first test is $m = 1 \ g = 0.001 \ kg$

The mass of matter converted to energy on second test $m_1 = 1.5 \ g = 1.5 *10^{-3} \ kg$

Generally the amount of energy that was released by the explosion is mathematically represented as

$E = m * c^2$

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3 years ago

What is an example of gravitational potential to kinetic to electrical current?

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3 years ago

Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h​

Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h