Answer:
The correct answer is D
shock waves
Explanation:
When a body approaches the speed of sound in the media, the waves it emits are getting closer and closer to each other, the envelope (sum) results in a kind of cylindrical cone that is similar to that formed in a supersonic process
The correct answer is D
When the speed of sound is exceeded, the body goes faster than the wave, so the so-called shock waves are formed.
They carry a lot of energy
Answer:
current will lead the voltage
Explanation:
From the bellow figure we can see the plot between the frequency and impedance
From the figure it is clear that when the frequency is less than the resonance frequency then the impedance decreases as the frequency increases it is possible only when impedance is capacitive in nature.
As the impedance is capacitive in nature so current will lead than the voltage
Answer:
(a) Region of higher potential
(b) ΔV=1.911V
Explanation:
For Part (a)
Proton moves into a region of higher potential because it must goes in opposite direction of force to get rest
For Part (b)
Potential difference we can calculate bu definition of kinetic energy
ΔK=mv²/2= -qΔV
express in ΔV
ΔV= -mv²/2q
Substitute the given values
So
ΔV= -mv²/2q

ΔV=1.911V
Answer:
156.26N
Explanation:
The data needed are incomplete. Let the acceleration of the body be 3.5m/s²
Other given parameters
Mass = 1.35×10^1 = 13.5kg
coefficient of friction between the tires and the road = 0.850
Acceleration due to gravity = 9.8m/s²
According to Newton's second law:
Fnet = ma
Fnet = Fapp - Ff
Fapp is the applied force
Ff is the frictional force = umg
The equation becomes:
Fapp - Ff = ma
Fapp-umg = ma
Fapp - 0.85(13.5)(9.8) = 13.5(3.5)
Fapp - 109.0125 = 47.25
Fapp = 47.25+109.0125
Fapp = 156.2625N
Hence the applied force that caused the acceleration is 156.26N
Note that the acceleration of the car was assumed. Any value of acceleration can be used for the calculation.
The answer should be "The object with the greater mass should be attached to the spring with the smaller <span>spring constant."
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