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Oduvanchick [21]
3 years ago
12

96/64 reduced to its lowest term

Engineering
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:

3/2

Explanation:

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A power of 100 kW (105 W) is delivered to the other side of a city by a pair of power lines, between which the voltage is 12,000
vivado [14]

Answer:

I = 8.3 Amp

potential drop = 83 V

Explanation:

Power = 100 KW

V = 12,000 V

R = 10 ohms

a)

Calculate current I in each wire:

P = I*V

I = P / V

I = 100 / 12 = 8.333 A

b)

Calculate potential drop in each wire:

V = I*R

V = (8.3) * (10)

V = 83 V

3 0
4 years ago
If you know that the change in entropy of a system where heat was added is 12 J/K, and that the temperature of the system is 250
SVEN [57.7K]

Solution:

Given:

Change in entropy of the system, ΔS = 12J/K

Temperature of the system, T_{o} = 250K

Now, we know that the change in entropy of a system is given by the formula:

ΔS = \frac{\Delta Q}{T_{o}}

Amount of heat added, ΔQ = \Delta S\times T_{o}

ΔQ = 3000J

3 0
3 years ago
A person is interested in becoming an electrician. What are some appropriate types of preparation that this individual can consi
Alchen [17]

Answer:

Four-year college degree I think

3 0
3 years ago
Read 2 more answers
A harmonic oscillator with spring constant, k, and mass, m, loses 3 quanta of energy, leading to the emission of a photon.
Monica [59]

Answer: (a). E = 3.1656×10³⁴ √k/m  

(b). f = 9.246 × 10¹² Hz

(c). Infrared region.

Explanation:

From Quantum Theory,

The energy of a proton is proportional to the frequency, from the equation;

E = hf

where E = energy in joules

h = planck's constant i.e. 6.626*10³⁴ Js

f = frequency

(a). from E = hf = 1 quanta

    f = ω/2π

where ω = √k/m

consider 3 quanta of energy is lost;

E = 3hf = 3h/2π × √k/m

E = (3×6.626×10³⁴ / 2π) × √k/m

E = 3.1656×10³⁴ √k/m    

(b). given from the question that K = 15 N/m

and mass M = 4 × 10⁻²⁶ kg

To get the frequency of the emitted photon,

Ephoton =hf = 3h/2π × √k/m (h cancels out)

f = 3h/2π × √k/m

f =  3h/2π × (√15 / 4 × 10⁻²⁶ )

f = 9.246 × 10¹² Hz

(c). The region of electromagnetic spectrum, the photon belongs to is the Infrared Spectrum because the frequency ranges from about 3 GHz to  400 THz in the electromagnetic spectrum.

6 0
3 years ago
When checking the resistance of a dual voltage wye motor, there should be ____ resistance readings. 1) twelve 2) six 3) three
hjlf

Answer:

1) twelve

Explanation:

The dual voltage motors are used in day to day operations. The wye is connected with 9 lead motors. Maximum resistance can be obtained if the resistance are connected in series. To check resistance of dual voltage wye motor there must be twelve resistance readings of 1 ohm each.

8 0
3 years ago
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