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charle [14.2K]
3 years ago
7

At a location near the equator, the earth’s magnetic field is horizontal and points north. An electron is moving vertically upwa

rd from the ground. What is the direction of the magnetic force that acts on the electron?(a) North (b) East (c) South (d) West (e) The magnetic force is zero.

Physics
2 answers:
ivann1987 [24]3 years ago
3 0

Answer:

(b) EAST

Explanation:

you can assume that the magnetic field points rightward, that is, in the positive x direction (NORTH). Furthermore, you can assume that the direction of the motion of the electron is in the positive y direction. Hence, you have:

\vec{B}=B_o\hat{i}\\\\\vec{v}=v_o\hat{j}

You use the Lorentz formula to known which is the direction of the magnetic force over the electron:

F=qv\ X\ B

which implies the cross product between the unitary vecors j and i, that is

\hat{i} \ X\ \hat{j} = -\hat{k}  (WEST)

However, the minus sign of the charge of the electron changes the direction 180°. Hence, the direction is k. That is, to the EAST

Rina8888 [55]3 years ago
3 0

Answer:

The electron will move east.

Explanation:

According to fleming's left hand rule for when the field and current are at right angles, the first finger represents the field's direction ( north to south), the second finger represents the current direction ( + to -) and the thumb represents the direction of motion..

See image below.

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Answer:

It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

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2 years ago
A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string
Darya [45]

Answer:

a

The  speed of  wave is   v_1  = 129.1 \ m/s

b

The new speed of the two waves is v =  129.1 \ m/s

Explanation:

From the question we are told that

    The mass of the string is  m  =  60 \ g  =  60 *10^{-3} \ kg

    The length is  l  =  2.0 \ m

    The tension is  T  = 500 \ N

Now the velocity of the first wave is mathematically represented as

     v_1  = \sqrt{ \frac{T}{\mu} }

Where  \mu is the linear density which is mathematically represented as

      \mu  =  \frac{m}{l}

substituting values    

     \mu  =  \frac{ 60 *10^{-3}}{2.0 }

     \mu  =  0.03\ kg/m

So

   v_1  = \sqrt{ \frac{500}{0.03} }

   v_1  = 129.1 \ m/s

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

     

8 0
4 years ago
A wave travelling 140 m/sec with a wavelength of 4.0 m has what frequency? _______________Meters / Hz / seconds
valentina_108 [34]

Answer:

The frequency of a wave is 35 Hz.

Explanation:

Speed of a wave is 140 m/s

Wavelength of a wave is 4 m

It is required to find the frequency. The relation between frequency, speed and the wavelength of a wave is given by :

v=f\lambda

f is frequency

f=\dfrac{v}{\lambda}\\\\f=\dfrac{140\ m/s}{4\ m}\\\\f=35\ Hz

So, the frequency of a wave is 35 Hz.

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3 years ago
How are scientific theories different than laws or hypotheses?
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Answer:The answer is A

Explanation:

3 0
3 years ago
Read 2 more answers
A car decelerates at a rate of 3.8 m/s2 for 12 seconds. The car’s initial speed was 65 m/s. What was the car’s final speed?
Ostrovityanka [42]
For an uniformly accelerated motion, the final velocity is given by:
v_f = v_i +at
where vi is the initial speed, a is the acceleration, and t the time interval.
In our problem, v_i=65 m/s, a=-3.8 m/s^2 (with negative sign, because the car is decelerating), and t=12 s. Substituting, 
v_f = 65 m/s+(-3.8 m/s^2)(12 s)=19.4 m/s

4 0
3 years ago
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