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charle [14.2K]
3 years ago
7

At a location near the equator, the earth’s magnetic field is horizontal and points north. An electron is moving vertically upwa

rd from the ground. What is the direction of the magnetic force that acts on the electron?(a) North (b) East (c) South (d) West (e) The magnetic force is zero.

Physics
2 answers:
ivann1987 [24]3 years ago
3 0

Answer:

(b) EAST

Explanation:

you can assume that the magnetic field points rightward, that is, in the positive x direction (NORTH). Furthermore, you can assume that the direction of the motion of the electron is in the positive y direction. Hence, you have:

\vec{B}=B_o\hat{i}\\\\\vec{v}=v_o\hat{j}

You use the Lorentz formula to known which is the direction of the magnetic force over the electron:

F=qv\ X\ B

which implies the cross product between the unitary vecors j and i, that is

\hat{i} \ X\ \hat{j} = -\hat{k}  (WEST)

However, the minus sign of the charge of the electron changes the direction 180°. Hence, the direction is k. That is, to the EAST

Rina8888 [55]3 years ago
3 0

Answer:

The electron will move east.

Explanation:

According to fleming's left hand rule for when the field and current are at right angles, the first finger represents the field's direction ( north to south), the second finger represents the current direction ( + to -) and the thumb represents the direction of motion..

See image below.

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Harman [31]

Answer: 11.1cm

Explanation:

Object distance (u) = 32cm

Image distance(v) = 17cm

Focal length(f) =?

Lens formular:

1/f = 1/u + 1/v

1/f = 1/32 + 1/17

Taking the L. C. M of 17 and 32

1/f = (17 + 32) / 544

1/f = 49/544

Taking the reciprocal

f = 544/49

f = 11.1 cm

Therefore, Focal length of the lens is 11.1cm

7 0
3 years ago
A fisherman has caught a very large, 5.0kg fish from a dock that is 2.0m above the water. He is using lightweightfishing line th
agasfer [191]

Answer:

t = 2 s

Explanation:

As we know that fish is pulled upwards with uniform maximum acceleration

then we will have

T - mg = ma

here we know that maximum possible acceleration of so that string will not break is given as

T = 54 N

now we have

54 - (5 \times 9.8) = 5 a

a = 1 m/s^2

now for such acceleration we can use kinematics

d = \frac{1}{2}at^2

2 = \frac{1}{2}(1) t^2

t = 2 s

7 0
3 years ago
a waterwheel built in Hamah, Syria, has a radius of 20 m . If the tangential velocity at the wheels edge is 7.85 m/s , what is t
gtnhenbr [62]

Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity  = 7.85m/s

Unknown:

Centripetal acceleration  = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

 it is mathematically given as;

       a  = \frac{v^{2} }{r}  

v is the tangential velocity

r is the radius

      a  = \frac{7.85^{2} }{20}   = 3.08m/s²

4 0
2 years ago
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Arisa [49]

Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

              = 1/2 (6 X 15)

              = 1/2 (90)

              = 45 meters

Hence, the object traveled 45 meters.

4 0
3 years ago
What is the horsepower of a 1,500 kg car that can go to the top of a 360 m high hill in exactly 1 min?
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Answer:

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P = 88,200 watts

P = 88,200 watts / 746 watts / hp = 118 hp

7 0
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