Answer:
The final velocity of the car is 26.65 m/s.
Explanation:
Given;
acceleration of the racecar, a = 6.5 m/s²
initial velocity of the car, u = 0
time of motion, t = 4.1 s
The final velocity of the car is given by;
v = u + at
where;
v is the final velocity of the car
suvstitute the givens
v = 0 + (6.5)(4.1)
v = 26.65 m/s.
Therefore, the final velocity of the car is 26.65 m/s.
 
        
             
        
        
        
Answer:
162500000.   
Explanation:
 Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as

I=Current
q=Charge
t=time
q= I t
q= 260 m t 
The total number of electron = n
q= n e

n=162500000 t

The number of electron passe per second will be 162500000.
 
        
             
        
        
        
D) waves are used to transmit the rail signal though the air. these waves are encoded at different frequencies for different stations
 
        
                    
             
        
        
        
Answer a would be correct since velocity is a vector and has a magnitude and a direction. In this case v₁ = - v₂.