Answer:
i have no clue i just need brailnly points
Explanation:
For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.
<h3>What is displacement?</h3>
The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.
In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.
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A line starts at (0, 2) and ends at (6, 8) in v-t graph
Displacement is equal to the area of a triangle and a rectangle formed under the line.
Area = 1/2 base x height + length x breadth
Area = 1/2 x 6x 6 + 6x2
Area = 18 +12
Area = 30 m
Thus, the displacement is 30 m.
Learn more about displacement.
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Answer:
E. d and O
Explanation:
"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".
According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".
The destructive interference for a single slit is given by:
Where
d is the slit width
is the light's wavelength
is the angle relative to the original direction of the light
m is the order od the minimum
I represent the intensity
When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.
The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
<h3>What is an electric field?</h3>
An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.
The given data in the problem is given by;
E is the electric field = (200 N/C)
d is the distance = 5.0 cm.=0.05 m
Q is the charge of electrons= 1.602 x 10^-19 C
The formula for electric potential is given by;
The work is defined as the product of the potential difference and charge of an electron.
Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.
To learn more about the electric field refer to the link;
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