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kogti [31]
3 years ago
9

An ideal gas goes through an expansion process where the volume of the gas doubles. Which process will lead to a larger work out

put, an isothermal process or a polytropic process with n = 1.25?
Engineering
1 answer:
KatRina [158]3 years ago
4 0

Answer:

The correct answer is: The process equation is PV^n=C

Explanation:

The isothermal process drops the pressure slower with n=1 and region beneath the curve is smaller then, meanwhile the polytropic process with n=1.25 gets to drop the pressure faster than isothermal.

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How many broadcast or vlan is in this switchs and router ? and why? ​
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Answer:The move from hubs (shared networks) to switched networks was a big improvement. Control over collisions, increased throughput, and the additional features offered by switches all provide ample incentive to upgrade infrastructure. But Layer 2 switched topologies are not without their difficulties. Extensive flat topologies can create congested broadcast domains and can involve compromises with security, redundancy, and load balancing. These issues can be mitigated through the use of virtual local area networks, or VLANs. This chapter provides the structure and operation of VLANs as standardized in IEEE 802.1Q. This discussion will include trunking methods used for interconnecting devices on VLANs.

Problem: Big Broadcast Domains

With any single shared media LAN segment, transmissions propagate through the entire segment. As traffic activity increases, more collisions occur and transmitting nodes must back off and wait before attempting the transmission again. While the collision is cleared, other nodes must also wait, further increasing congestion on the LAN segment.

The left side of Figure 4-1 depicts a small network in which PC 2 and PC 4 attempt transmissions at the same time. The frames propagate away from the computers, eventually colliding with each other somewhere in between the two nodes as shown on the right. The increased voltage and power then propagate away from the scene of the collision. Note that the collision does not continue past the switches on either end. These are the boundaries of the collision domain. This is one of the primary reasons for switches replacing hubs. Hubs (and access points) simply do not scale well as network traffic increases.

7 0
3 years ago
Technician A says that a pilot bearing should always be replaced when a clutch is replaced. Technician B says that oft-dampened
grigory [225]

There are different kinds of care given to machine parts. Technician A says that a pilot bearing should always be replaced when a clutch is replaced is a true statement and thus is the only correct one.

<h3>When should I replace my pilot bearing?</h3>
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Learn more about Machine parts from

brainly.com/question/835153

5 0
2 years ago
The numbers should be added to the merged array in an alternating pattern: first from list 1, then from list 2, then list 1 agai
Vinvika [58]

Answer:

According to the complete question, the code below gives the solution to the problem in Java with appropriate comments

Explanation:

import java.util.Scanner;

import java.lang.Math;

class Main {

  public static void main(String[] args) {

      int length = 0;

      boolean lengthCheck = true;

      Scanner scan = new Scanner(System.in);

      while (lengthCheck == true)

      {

          System.out.println("Enter an array length (must be 10 or greater):");

          length = scan.nextInt();

          if (length >= 10)

          {

              lengthCheck = false;

          }

      }

      int[] firstArray = new int[length];

      int[] secondArray = new int[length];

      System.out.print("\nFirst Array: ");

      for (int i = 0; i < length; i++)

      {

          firstArray[i] = (int) (Math.random() * 100) + 1;

          System.out.print(firstArray[i] + " ");

      }

      System.out.print("\n\nSecond Array: ");

      for (int i = 0; i < length; i++)

      {

          secondArray[i] = (int) (Math.random() * 100) + 1;

          System.out.print(secondArray[i] + " ");

      }

      System.out.println("\n");

     

     

/*

* A boolean array of length 100 to track list of number we have already added to merge list

*/

      boolean[] isAdded = new boolean[100];

      int[] merge = new int[(firstArray.length + secondArray.length)];

     

      int j=0;

      for (int i = 0; i < length; i++)

      {

          if(!isAdded[firstArray[i] - 1]) {

              merge[j] = firstArray[i];

              j++;

              isAdded[firstArray[i] - 1] = true;

          }

         

          if(!isAdded[secondArray[i] - 1]) {

              merge[j] = secondArray[i];

              j++;

              isAdded[secondArray[i] - 1] = true;

          }

         

      }

     

      System.out.print("Merged Array: ");

     

      for (int i = 0; i < 2*length && merge[i] != 0; i++)

      {

          System.out.print(merge[i] + " ");

      }

      System.out.println("\n");

     

  }

}

4 0
3 years ago
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