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Tresset [83]
3 years ago
6

The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which da

ta set represents constant acceleration?​

Physics
2 answers:
N76 [4]3 years ago
6 0

Answer:

A

Explanation:

on edge

RUDIKE [14]3 years ago
5 0

Answer:

The first graph is showing the constant acceleration (1 m/s)

Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

The last graph is showing constant velocity therefore there is no acceleration (a = 0)

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Your image appears 3.0 m from a plane mirror. How far IS YOUR IMAGE IN<br> RELATION TO YOU?*
Vsevolod [243]

Answer:

Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres

8 0
3 years ago
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A force is applied to a 30-kg object, resulting in an acceleration of 15 m/s. What is the force being applied to the object?
telo118 [61]
The sum of all forces applied to the object = (mass) x (acceleration)

The sum of all forces applied to the object = (30) x (15)

= <u>450 newtons</u>, in the direction of the acceleration.
 
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A dog leaps horizontally off a 70 m cliff with a speed of 6 m/s, how far from the base will the dog land?
iris [78.8K]

Answer:

\Delta x=22.67786838m

Explanation:

Let's use projectile motion equations. First of all we need to find the travel time. So we are going to use the next equation:

y-y_0=v_o*sin(\theta)*t-\frac{1}{2}*t^2 (1)

Where:

y=Final\hspace{3}position\hspace{3}at\hspace{3}y-axis

y_o=Initial\hspace{3}position\hspace{3}at\hspace{3}y-axis

v_o=initial\hspace{3}velocity

t=travel\hspace{3}time

g=gravity\hspace{3}constant

\theta=Initial\hspace{3}launch\hspace{3}angle

In this case:

\theta=0

Because the dog jumps horizontally

Let's asume the gravity constant as:

g=9.8

y=0

Because when the dog reach the base the height is 0

y_o=70

v_o=6

Now let's replace the data in (1)

y_o-\frac{1}{2} *(9.8)*t^2+70

Isolating t:

t=\pm\sqrt{\frac{2*70}{9.8} } =3.77964473

Finally let's find the horizontal displacement using this equation:

\Delta x=v_o*cos(\theta)*t

Replacing the data:

\Delta x=6*1*3.77964473=22.67786838m

8 0
3 years ago
I need help someone please...
hram777 [196]
D. Polar is your answer
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3 years ago
A cylindrical rod of length L is connected across a fixed potential difference, creating a current I through the rod. What would
Inessa05 [86]

Answer:

The value of current through the rod becomes half

i' = \frac{i}{2}

Explanation:

As per Ohm's law we know that the current through a resistor is given as

i = \frac{V}{R}

here we know that

R = \rho \frac{L}{A}

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

i = \frac{V A}{\rho L}

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same

so we will have

i' = \frac{VA}{\rho (2L)}

now from above two equations we have

\frac{i}{i'} = 2

so new current will become

i' = \frac{i}{2}

3 0
3 years ago
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