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Tresset [83]
3 years ago
6

The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which da

ta set represents constant acceleration?​

Physics
2 answers:
N76 [4]3 years ago
6 0

Answer:

A

Explanation:

on edge

RUDIKE [14]3 years ago
5 0

Answer:

The first graph is showing the constant acceleration (1 m/s)

Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

The last graph is showing constant velocity therefore there is no acceleration (a = 0)

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Please help, im stuck on this question
saw5 [17]

Answer:

A) .27 A

Explanation:

v = ir

i = v/r

equivalent r  =   45 * 90 / (45+90) = 30 ohms    ( for the two r in parallel)

i = 8v / 30 ohm = 267 mAmps

8 0
2 years ago
Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a
Fittoniya [83]

Explanation:

As we know that

time = distance/speed

The time used for firs half of the trip was

(1 mi)(12 mi/hour) = 1/12 hours = 5 minutes

The last half of the trip will took 10 minutes, 1/6 hour.

Speed = distance/ time

(1 mil) = (1/6h) = 6 mil/h

so the speed for last half of the trip was = 6mph

the average speed was

(2mil)(1/4 hour) = 8 mil/hour

So the ling's average speed was 8mph.

3 0
4 years ago
Pakistan and bangladesh are two countries on the subcontinent
gregori [183]

Answer:

Indian subcontinent  

Explanation:

The Indian subcontinent is a southern region and peninsula of Asia which include seven countries. The seven countries in Indian subcontinent are Pakistan, Bangladesh, India, Bhutan, Maldives, Sri Lanka and Nepal. According to Wikipedia, about 55 million years ago, the Indian subcontinent has land mass that rifted from Gondwana and merged with the Eurasian plate.

5 0
3 years ago
A point charge q1 = is located at the center of a thick conducting spherical shell of inner radius a = 2.2 cm and outer radius b
Yanka [14]

Answer:

Ex(P) = -3.602 x 10^6 N/C

Explanation:

  • given q1 = -5.7μC
  • q2 = 2.6 μC = the net charge on the conducting shell
  • inner radius of conducting shell = a = 2.2 cm =0.022m
  • outer radius of conducting shell = b = 4.5 cm = 0.045m

1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;

Ex(P) = k(q1+q2)/r^2

= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2

Ex(P) = -27.9 x 10^3/ 0.007744

Ex(P) = -3.602 x 10^6 N/C

7 0
4 years ago
When a force of 15 newtons is applied to a stationary chair, it starts moving. What can you say about the frictional force betwe
harkovskaia [24]
First you need to make a difference between friction while object is stationary and the friction while object is moving. Force required to start moving some object is slightly greater than force required to maintain objects movement. That means that to move a chair you need some force F1 but you can than slightly reduce force and chair will still be moving.

Now to the problem in this question: It can be said that "stationary friction force" is equal to 15 Newtons. Its also good to know that friction force between chair and floor while you are increasing your push is also increasing and is equal to force of your push. Once it reaches 15N which is it "critical value" for that chair, chair starts moving and friction force drops a little bit and now it is called friction force of moving chair.
3 0
3 years ago
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