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Dafna1 [17]
3 years ago
10

A man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east.

Physics
1 answer:
diamong [38]3 years ago
4 0

Answer:

<h2>i) 8.0m</h2><h2>ii) 6.32m</h2>

Explanation:

i) The total distance traveled will be the sum total of individual distances traveled by the man.

If the man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east, the total distance traveled will be expressed as; 1.5m+2m+4.5m

= 8.0m

ii) In order to get the man resultant displacement, we will use the Pythagoras theorem. Since the man travels a distance if 1.5 m and 4.5m towards east, the total distance taken towards east will be 6.0m and the distance traveled towards south is 2.0m. The resultant displacement of the man is expressed as;

R = \sqrt{x^{2}+y^{2}  }

Note that the eastward direction is the x-direction while the south direction is the y-direction.

x = 6.0m and y = 2.0m

R = \sqrt{6^{2}+2^{2}  } \\R = \sqrt{36+4}\\ R = \sqrt{40} \\R = 6.32m

The displacement of the man is 6.32m

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block of mass 5kgriding on a horizontal frictionlessxy-plane surface is subjected tothree applied forces:→F1= 12√2N[ 45◦]→F2= (8
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Answer:

(i) See attached image for the drawing

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y-component of F1 is    F1_y=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N

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x-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

y-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

Now we can calculate the components of the velocity of this mass after 2 seconds of being accelerated by this force, using the formula of acceleration times time:

x-component of the velocity is:     v_x=4\,*\,2=8\,m/s

y-component of the velocity is:     v_y=4\,*\,2=8\,m/s

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Read 2 more answers
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