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3 years ago

A man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east.

Physics

1 answer:

diamong [38]3 years ago

4 0

Answer:

Explanation:

i) The total distance traveled will be the sum total of individual distances traveled by the man.

If the man travels a distance if 1.5 m towards east ,then 2m towards south and 4.5 m towards east, the total distance traveled will be expressed as; 1.5m+2m+4.5m

= 8.0m

ii) In order to get the man resultant displacement, we will use the Pythagoras theorem. Since the man travels a distance if 1.5 m and 4.5m towards east, the total distance taken towards east will be 6.0m and the distance traveled towards south is 2.0m. The resultant displacement of the man is expressed as;

R = $\sqrt{x^{2}+y^{2} }$

Note that the eastward direction is the x-direction while the south direction is the y-direction.

x = 6.0m and y = 2.0m

$R = \sqrt{6^{2}+2^{2} } \\R = \sqrt{36+4}\\ R = \sqrt{40} \\R = 6.32m$

The displacement of the man is 6.32m

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A horizontal circular curve on a highway is designed for traffic moving at 60 km/h. If the radius of the curve is 150 m, and if

KengaRu [80]

Answer:

The value of the correct angle of banking for the road is $\theta = 67.76$ °

Explanation:

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3 years ago

A wheel has a rotational inertia of 16 kgm2. Over an interval of 2.0 s its angular velocity increases from 7.0 rad/s to 9.0 rad/

german

Answer:

<h2>128.61 Watts</h2>

Explanation:

Average power done by the torque is expressed as the ratio of the workdone by the toque to time.

Power = Workdone by torque/time

Workdone by the torque = $\tau \theta$ = $I\alpha * \theta$

I is the rotational inertia = 16kgm²

$\theta = angular\ displacement$

$\theta = 2 rev = 12.56 rad$

$\alpha \ is \ the\ angular\ acceleration$

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$\alpha = \frac{\omega_f^2- \omega_i^2}{2\theta}$

$\alpha = \frac{9.0^2- 7.0^2}{2(12.54)}\\\alpha = 1.28\ rad/s^{2}$

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