Answer:
I'm pretty sure it shows a direct relationship
Explanation:
Mechanical energy
I think
Answer:
25.59 m/s²
Explanation:
Using the formula for the force of static friction:
--- (1)
where;
static friction force
coefficient of static friction
N = normal force
Also, recall that:
F = mass × acceleration
Similarly, N = mg
here, due to min. acceleration of the car;

From equation (1)

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.
Thus,




where;
and g = 9.8 m/s²


second question: How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time?
Answer in units of s.
Answer:
Part 1: 28°
Part 2: 1.367
Explanation:
Part 1:
Given: 62°
Simple
θ = 90°- 62°
<u>θ = 28°</u>
Part 2:
Y-direction
Δy
![t_{1} =\frac{2[16.2sin(62)]}{9.8}](https://tex.z-dn.net/?f=t_%7B1%7D%20%3D%5Cfrac%7B2%5B16.2sin%2862%29%5D%7D%7B9.8%7D)

![0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}](https://tex.z-dn.net/?f=0%3D%5B16.2sin%2828%29%5Dt_%7B2%7D%2B1%2F2%28-9.8%29t_%7B2%7D%5E%7B2%7D)
![t_{2} =\frac{2[16.2sin(28)]}{9.8}](https://tex.z-dn.net/?f=t_%7B2%7D%20%3D%5Cfrac%7B2%5B16.2sin%2828%29%5D%7D%7B9.8%7D)

Δt
Δt
<u>Δt= 1.367s</u>
Hope it helps :)
Explanation:
mass, m = 5kg
initial velocity, u = 16m/s
final velocuty, v = -22m/s
change in momentum, ∆p = ?
∆p = m (v-u)
5(-22-16)
5(38)
∆p = 190kgm/s
check the calculations!