Unpolarized light with an intensity of 432 W/m^2 passes through three polarizing filters in a row, each of which is rotated 30 d
egrees from the one before it. Find the intensity of the light that emerges at the end
1 answer:
Answer:
40.5 W/m²
Explanation:
Intensity of unpolarized light = 432 W/m² = I₀
Intensity of light as it passes through first polarizer
I = I₀×0.5
⇒I = 432×0.5
⇒I = 216 W/m²
Intensity of light as it passes through second polarizer. So, Intensity after it passes through first polarizer is the input for the second polarizer
I = I₀×0.5 cos²30
⇒I = 216×0.75
⇒I = 162 W/m²
Intensity of light as it passes through third polarizer.
I = I₀×0.5 cos²30×cos²60
⇒I = 162×0.25
⇒I = 40.5 W/m²
Intensity of light at the end is 40.5 W/m²
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