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2 years ago

Use the image to determine the volume of the rock.

Physics

1 answer:

maria [59]2 years ago

6 0

Answer:

12 ml

Explanation:

The initial volume in the cylinder is 20 ml

adding the rock adds volume to the cylinder

the new volume is 32 ml .....the increase in volume is the volume of the rock : 32 - 20 = 12 ml volume of rock

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3 years ago

A particle with charge +6.70 nC is in a uniform electric field directed to the left. Another force, in addition to the electric

mina [271]

Answer:

a) 4.6*10^{-5} J

b) 6133.33 J/C

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Explanation:

(a) We have that the change in the kinetic energy equals the net work over the charge. Hence we have

$\Delta E_K=W-W_E$

where Ek is the kinetic energy, W is the work of the external force and WE is the work done by the electric field. By replacing we obtain:

$W_E=W-\Delta E_k=7.60*10^{-5}J-3*10^{-5}J=4.6*10^{-5}J$

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(c) With the work done by the electric force we can calculate the Electric field. By using the following formula we obtain:

$W_E=qEd\\\\E=\frac{W_E}{qd}=\frac{4.6*10^{-5}J}{(7.5*10^{-9}C)(6.50*10^{-2}m)}=94358.9\frac{N}{C}$

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3 years ago

Read 2 more answers

The CEO, ellen misk, left her martian office but accidentally left a cylindricall can of coke (3.1 inches in diameter, 5.42 inch

iren2701 [21]

Answer:

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Explanation:

First, we will find the force exerted by the can on the table. This force will be equal to the weight of the can:

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Now, the weight is given as:

Weight = mg

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m = (2.48 N)/(9.8 m/s²)

m = 0.25 kg

Now, we calculate volume of can:

Volume = (Area)(Height) = (4.8 x 10⁻³ m²)(5.42 in)(0.0254 m/1 in)

Volume = 6.6 x 10⁻⁴ m³

Hence, the density of can will be:

Density of Can = m/Volume = 0.25 kg/6.6 x 10⁻⁴ m³

Density of Can = 378.32 kg/m³

So, the specific gravity of Can will be:

Specific Gravity = Density of Can/Density of Water

Specific Gravity = (378.32 kg/m³)/(1000 kg/m³)

<u>Specific Gravity = 0.378</u>

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