Answer:
Explanation:
Impedence of the circuit = peak voltage / peak current
= 5.8 / 51 x 10⁻³
= 113.725 ohm.
1 / wC =113.725
w = 1 / (113.725 x 22 x 10⁻⁹ )
= 10⁹ / 2.5 x 10³
=10⁶ / 2.5
40 x 10⁴
frequency n = 40 x 10⁴ / 2 x 3.14
6.37 x 10⁴ Hz.
b ) charge on the capacitor = 1 C
V = Q / C
= Charge / capacitor
= 1 / 22 x 10⁻⁹
4.54 x 10⁷ V.
Answer: 3kg: 14.7 6kg: 29.4 9kg: 44.1
Explanation: just did it on Edge
Answer: 86.47 g of carbon-14 must have been present in the sample 11,430 years ago.
Explanation:
Half-life of sample of carbon -14= 5,730 days

Let the sample present 11,430 years(t) ago = 
Sample left till today ,N= 0.060 g

![ln[N]=ln[N]_o-\lambda t](https://tex.z-dn.net/?f=ln%5BN%5D%3Dln%5BN%5D_o-%5Clambda%20t)
![\log[0.060 g]=\log[N_o]-2.303\times 0.00012 day^{-1}\times 11,430 days](https://tex.z-dn.net/?f=%5Clog%5B0.060%20g%5D%3D%5Clog%5BN_o%5D-2.303%5Ctimes%200.00012%20day%5E%7B-1%7D%5Ctimes%2011%2C430%20days)
![\log[N_o]=1.9369](https://tex.z-dn.net/?f=%5Clog%5BN_o%5D%3D1.9369)

86.47 g of carbon-14 must have been present in the sample 11,430 years ago.