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pishuonlain [190]
3 years ago
11

Match the following. 1. A mixture that does not have a uniform composition and the individual components remain distinct. polar

2. A mixture that does have a uniform composition throughout and is always in the same state. insoluble 3. A substance that will not dissolve in a solvent. homogeneous 4. A homogeneous mixture saturated 5. A molecule with no internal charge variation due to bonding. solution 6. a molecule with an uneven distribution of charge due to unequal sharing of electrons during bonding nonpolar 7. A solution which has dissolved as much solute as it can at a particular temperature. unsaturated 8. A solution which is still able to dissolve solute. heterogeneous
Chemistry
1 answer:
Ganezh [65]3 years ago
8 0

Answer:

Explanation:

1. A mixture that does not have a uniform composition and the individual components remain distinct.

HETEROGENEOUS

An heterogeous mixture is a mixture with components in different phases.

2. A mixture that does have a uniform composition throughout and is always in the same state.

HOMOGENOUS

Homogenous mixtures have just one phase that is uniform all through.

3. A substance that will not dissolve in a solvent.

INSOLUBLE

When a solute cannot dissolve in a solvent to form a solution, we say it is insoluble.

4. A homogeneous mixture

SOLUTION

Solutions are made up of homogenous mixtures solute and solvent.

5. A molecule with no internal charge variation due to bonding.

NON-POLAR

Even distribution of charges especially between species whose electronegativity difference is 0 would lead to the formation of a non-polar compound. Here,

6. A molecule with an uneven distribution of charge due to unequal sharing of electrons during bonding

POLAR

Unequal sharing of electrons forms a polar compound. The more electronegative attracts the shared electron to itself and there is separation of charges. This leads to polarity.

7. A solution which has dissolved as much solute as it can at a particular temperature.

SATURATED

A saturated solution cannot dissolve more solute beacuse it contains enough solute as it can dissolve at a temperature.

8. A solution which is still able to dissolve solute.

UNSATURATED

An unsaturated solution is able to dissolve more solute.

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b.

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7 0
3 years ago
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Solid iron metal reacts with solid sulfur at room temperature to produce solid iron (ll) sulfide? Express as a chemical equation
kupik [55]
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5 0
2 years ago
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

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8 0
3 years ago
What is the electronegativity difference between oxygen and fluorine? What type of bond is this?
JulijaS [17]

Answer:

Veja, por exemplo, que os elementos mais eletronegativos são os que estão no canto superior direito da tabela, isto é, o flúor (4,0) e o oxigênio (3,5), e os menos eletronegativos são os que estão no canto inferior esquerdo, que são o frâncio (0,8) e o césio (0,8).

Explanation:

8 0
3 years ago
Nitrogen gas is being withdrawn at the rate of 4.5 g/s from a 0.15-m3 cylinder, initially containing the gas at a pressure of 10
faust18 [17]

Answer:

Final temperature = 152.57K,

Pressure = 0.6907 bar.

dT/dt = - 1,151 K/s.

Explanation:

The first thing to do here is to write out the equation for mass balance as given below:

dN/dt = N -------------------------------------------------------------------------------------------(1).

N = P/T, then, substitute the values given in the question into:

d[p/T]/ dt = [- 4.5/28 × 8.314]/0.15 = - 8.9 × 10⁻⁵ bar/K.s.

Thus, there is the need to integrate, Integrate [p/T]f = 10/320 - 8.9 × 10⁻⁵ bar/K.s. ------------------------------------(2).

NB; fT = final temperature, fP = final pressure and iT = initial temperature.

Also, [ fT]³⁰/₈.₃₁₄/ [fP] = [iT]³⁰/₈.₃₁₄/ Pi] = [ 320]³⁰/₈.₃₁₄/ 10.

Therefore, [fT]³⁰/₈.₃₁₄ = 109.52 × 10⁶.

Final temperature=  [fP]³⁰/₈.₃₁₄ × 169.05.

Note that fP/ [fP]³⁰/₈.₃₁₄ × 169.05 = 10/320 - 8.9 × 10⁻⁵.

Therefore, [fP]¹ ⁻ ³⁰/₈.₃₁₄ = 0.7651.

Hence, Final temperature = 152.57K,

Pressure = 0.6907 bar

dT/ dt = N[RT]² / Cv . PV.

R = 30 - 8.314 = 21.86 J/mol K.

Then, the rate of change of the gas temperature at this time = dT/dt = - 1,151 K/s.

4 0
3 years ago
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