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Katyanochek1 [597]
3 years ago
5

We can block light by placing obstacles in its path, but it’s much more difficult to block sound. Why?

Physics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

Because light propagate in a straight path, while sound moves in all directions.

Explanation:

The rectilinear propagation of light proves that light travels on a straight path. With this, any opaque obstacle in its path would absorb the major fraction and reflect little fraction of the light. Light is an electromagnetic wave and transverse in nature.

Sound travels in all directions and it requires material medium (majorly air)  for its propagation. Thus, it is not easy to obstruct the propagation of sound. It is a mechanical wave and longitudinal in nature.

Olin [163]3 years ago
7 0
Sound spreads through some kind of medium. Most of the time the medium is usually air. Sound can go through walls, like when you are playing really loud music and the neighbors tell you its to loud, you can't block it because it can travel through objects. Light does not need a medium to travel with. if you put a light in a room with no windows and no cracks, and you seal off the door the light can't escape that room, but if you did the same thing with sound it would travel trough the walls.
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The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

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Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The energy in terms of the charge and potential difference is;

E= qV

60=5 C × V

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The electric current is found as;

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\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A

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When light passes through an ___ it is separated into its component colors
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tensa zangetsu [6.8K]

Answer:

A 1.5 metres per second squared B 0 C 6 0.5

b) 9m

Explanation:

a= v-a/t

a= acceleration measured in metres per second squared

v= final speed measured in metres per second

u= initial speed measured in metres per second

t= time measured in second

A

a=v-a/t

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a= 1.5 metres per second squared

Distance in a velocity time graph = area under

To calculate the distance in the first 4 seconds

You divide the graph into triangles and rectangles

Area A (triangle )= 1/2 × base × height

=1÷2 ×2×3

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Area B (rectangle)= L×B

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Afina-wow [57]

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