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2 years ago

Determine the speed at which the medicine leaves the needle

Physics

1 answer:

Ivan2 years ago

5 0

The speed at which the medicine leaves the needle is 2.462 m/s

<h3>What is Bernoulli's theorem?</h3>

When an incompressible, ideal fluid is flowing through a tube or pipe, the total energy remains constant.

p₁ /ρg + v₁²/2g +z₁ = p₂ /ρg + v₂²/2g +z₂

Where, p/ρg = pressure energy

v²/2g = kinetic energy

z = potential energy

Given is during an injection, pressure in the barrel of syringe is 1.03 atm while pressure in the needle section is 1.00 atm. Assuming the syringe lays horizontally and mass density of the liquid medicine ρ =1000 kg/m³.

The fluid is initially at rest.

Using the Bernoulli's equation, we have

v₁² - v₂²= 2 x (p₂ -p₁) / ρ

Substituting the values, we get

0 - v₂² = 2 x (1.00 -1.03) x 1.01 x 10⁵ /1000

v₂² = 6.06

v₂ = 2.462 m/s

Thus, the speed at which the medicine leaves the needle is 2.462 m/s

Learn more about Bernoulli's theorem

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Explanation:

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u = 0 is the initial velocity

$a=25 m/s^2$ is the acceleration

Substituting t = 29 s,

$v=0+(25)(29)=725 m/s$

Now we can find the distance covered in the last second of motion by using

$s=ut+\frac{1}{2}at^2$

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Substituting,

$s=(725)(1)+\frac{1}{2}(25)(1)^2=737.5 m$

Note that the acceleration of $25 m/s^2$ is not realistic for a car, but I still have used the data of the problem.

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3 years ago

A boy whirls a ball on a string in a horizontal circle of radius 1 m. How many revolutions per minute must the ball make if its

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Answer:

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Explanation:

Given that,

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We know that,

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We need to calculate the revolutions in one second

Using formula of centripetal acceleration

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Using value for the revolutions per minute

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