The speed at which the medicine leaves the needle is 2.462 m/s
<h3>What is Bernoulli's theorem?</h3>
When an incompressible, ideal fluid is flowing through a tube or pipe, the total energy remains constant.
p₁ /ρg + v₁²/2g +z₁ = p₂ /ρg + v₂²/2g +z₂
Where, p/ρg = pressure energy
v²/2g = kinetic energy
z = potential energy
Given is during an injection, pressure in the barrel of syringe is 1.03 atm while pressure in the needle section is 1.00 atm. Assuming the syringe lays horizontally and mass density of the liquid medicine ρ =1000 kg/m³.
The fluid is initially at rest.
Using the Bernoulli's equation, we have
v₁² - v₂²= 2 x (p₂ -p₁) / ρ
Substituting the values, we get
0 - v₂² = 2 x (1.00 -1.03) x 1.01 x 10⁵ /1000
v₂² = 6.06
v₂ = 2.462 m/s
Thus, the speed at which the medicine leaves the needle is 2.462 m/s
Learn more about Bernoulli's theorem
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