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2 years ago

Which part of the electromagnetic spectrum has a lower frequency than visible light? x-rays ultraviolet infrared gamma rays

Physics

2 answers:

Ivahew [28]2 years ago

8 0

The answer is infrared.

nikdorinn [45]2 years ago

4 0

Lower frequency: Radio waves, microwaves and infrared have lower frequency than visible light.

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In pushes a 500 N crate with an applied force of 1450 N to the left. He encounters a fridtional force of 200 N and his evil co-w

Butoxors [25]

Answer:

C. 750 N. left

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

mass of crate m= 500N

1450N force left

Frictional force of 200 N -----this opposes the motion

500 N opposing force to the right

The net force is equal to the summation of all the forces in Newton

Net force= -1450+200+500

Net force=-750N

The direction is right

5 0

2 years ago

Carlos has eight marbles that are all the same size. he knows that one marble has a mass of 10 grams. to find out the total mass

AURORKA [14]

Carlos lost his marbles

4 0

2 years ago

You throw a balloon that floats in the air with a velocity of 2 m / s south . If the wind speed is 5 m / s west , how far south

zvonat [6]

Answer:

The distance traveled by the balloon is 10.77 m

Explanation:

velocity of the ball, $v_b$ = 2 m/s south

velocity of the air, $v_a$ = 5 m/s west

To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.

| 2m/s

↓

5m/s ←------------------

the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.

R² = 5² + 2²

R² = 29

R = √29

R = 5.385 m/s

The distance traveled by the balloon is calculated as;

d = R x t

where;

t is time of the motion = 2 seconds

d = 5.385 x 2

d = 10.77 m

Therefore, the distance traveled by the balloon is 10.77 m.

4 0

2 years ago

The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

kotykmax [81]

Answer:

$2.1\times 10^{-12} c$

Explanation:

We are given that

Surface area of membrane= $5.3\times 10^{-9} m^2$

Thickness of membrane= $1.1\times 10^{-8} m$

Assume that membrane behave like a parallel plate capacitor.

Dielectric constant=5.9

Potential difference between surfaces=85.9 mV

We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

$C=\frac{k\epsilon_0 A}{d}$

Substitute the values then we get

Capacitance between parallel plate capacitor= $\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}$

$C=0.25\times 10^{-12}F$

V= $85.9 mV=85.9\times 10^{-3}$

$Q=CV$

$Q=0.25\times 10^{-12}\times 85.9\times 10^{3}=2.1\times 10^{-12} c$

Hence, the charge resides on the outer surface= $2.1\times 10^{-12} c$

5 0

3 years ago

Read 2 more answers

What happens to a path of a light ray parallel to the principal axis, after it passes through a converging

Simora [160]

Answer: The ray that passes through the focal point on the way to the lens will refract and travel parallel to the principal axis. ... All three rays should intersect at exactly the same point.

Explanation: Once these incident rays strike the lens, refract them according to the three rules of refraction for converging lenses.

3 0

2 years ago