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ivolga24 [154]
3 years ago
10

How can the sun have both a brightness of -26.73 and 4.83? Explain what these numbers mean.

Physics
1 answer:
Assoli18 [71]3 years ago
3 0
The Sun has<span> an "absolute magnitude" of </span>4.83 and an "apparent" magnitude of -26.8. (Which is the difference between the numbers). <span>Scientists use what is know as "</span>Absolute" Magnitude<span> to help them understand and compute how bright a star really is. The "</span>absolute" magnitude<span> of an object, such as a star, equals how bright that object would look if it were 10 parsecs, or 32.6 light years away from the Earth.</span>
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Describe the difference between the velocity graph made walking at a steady rate and the velocity graph made at an increasing ra
levacccp [35]

Answer:

The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0

On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.

8 0
3 years ago
Of elements N, O, Cl, Na, and Which two would likely have similar chemical properties and why
velikii [3]
<span>Oxygen and Nitrogen would be the most similar of the elements listed, because they are the closest in the periodic table. This isn't a very good reason for anything, but the two do have some similar properties. They are both non-metals, they are both highly electronegative, they are both diatmoic gasses in their natural states, they have a similar number of valence electrons, they are both generally oxidizing agents. Oxygen and Chlorine are also quite similar, but not quite as similar as Oxygen and Nitrogen.</span>
3 0
3 years ago
If the mass of an object is 10 Kg and it experiences a Net force of 60 Newtons. What is the acceleration?
Solnce55 [7]

Answer:

6 m/s^2

Explanation:

F = ma

60N = (10 kg)a

a = 6m/s^2

3 0
3 years ago
A 0.8 m length of wire is formed into a single turn, square loop in which there is a current of 12 A. The loop is placed in magn
rewona [7]

Answer:

0.073 N-m

Explanation:

i = 12 A, l = 0.8 m, B = 0.12 T

The circumference of the loop is 0.8 m.

Let r be the radius of the loop.

2 x 3.14 x r = 0.8

r = 0.127 m

Maximum Torque = i x A x B

Maximum Torque = 12 x 3.14 x 0.127 x 0.127 x 0.12 = 0.073 N-m

8 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
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