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tensa zangetsu [6.8K]
3 years ago
12

Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

s needed to produce 120 grams of carbon dioxide? C6H12O6 + 6O2 -> 6CO2 + 6H2O
Chemistry
1 answer:
defon3 years ago
5 0

How much oxygen is needed to produce 120 grams of carbon dioxide? C6H12O6 + 6O2 -> 6CO2 + 6H2O

Let's convert 120 grams of CO2 to moles first using the molar mass, 44.01 g/mol. 120 grams CO2 * (1 mole CO2/44.01 grams CO2) = 2.73 moles CO2

Then using the given reaction, we will get the amount of moles O2 needed using the ratios of the chemicals that react.

2.73 moles CO2 * (6 moles O2/6 moles CO2) = 2.73 moles O2 * ( 32 grams O2 / 1 mole O2) = 87.25 grams O2 <--answer

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How many molecules of oxygen are needed to make 3.5 oxygens of water?​
max2010maxim [7]

Answer:

57.6g

Explanation:

So, if in one mole of water, 16 g of oxygen atom is present. Then, in 3.6 moles of water, the mass of oxygen present will be 3.6×16=57.6g. Therefore, the amount of oxygen present in 3.6 g water is option (B)- 57.6 g.

8 0
3 years ago
Active and inactive volcano in philipines?
finlep [7]

355 volcanoes in the Philippines are inactive.

24 volcanoes are active

3 0
3 years ago
If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the
Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

8 0
3 years ago
At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

5 0
3 years ago
Read 2 more answers
Which of the following is considered a drawback to using wind energy as a source of power?
Olin [163]

Answer:

Option (3)

Explanation:

Wind energy is directly derived from the wind. In the places where wind blowing is quite frequent, there wind mills are being set up, and the turbines in it rotates due to the prevailing wind. Due to this continuous motion of turbines, it collects the wind energy and it is being transferred into electrical energy.

It is cost-effective and does not produce any kind of pollution and is completely a renewable energy, that it can generated again and again.

It does have certain drawbacks also, because <u>the area may sometime do not experience constant wind, due to which it cannot store energy. So frequent wind blowing areas are the best place to set up windmills</u>.

Thus, the correct answer is option (3)

5 0
3 years ago
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