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garri49 [273]
3 years ago
8

F. give some examples of how it might be useful to know the melting or boiling points of a substance. think in terms of both sci

entific and commercial/industrial settings.
Chemistry
1 answer:
Delvig [45]3 years ago
6 0
Hello!

To know the melting or boiling points of substances is extremely important:

-In a Scientific Setting, it would help identify and separate unknown substances, as the melting or boiling points are unique for each compound, and their determination is useful for identifying and separating them. 

-In an Industrial Setting, it would help engineers to know the storage temperatures of compounds. Some compounds if stored at temperatures above their boiling points will evaporate and when stored at temperatures under their melting points will solidify. In some cases this behavior is undesired and knowledge of boiling and melting points is important. 

Have a nice day!
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Which of the following statements concerning equilibrium constants is true? The equilibrium constant of the reverse reaction is
Brut [27]

Answer:

When the coefficients in a balanced chemical reaction are multiplied by two, the equilibrium constant is not affected.

Explanation:

The equilibrium constant of a reaction is known to remain steady.

Even if all the coefficients of all the species in the reaction are multiplied by two, the value of the equilibrium constant will reamin the same because the equilibrium position will not change as a result of that.

3 0
3 years ago
"Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units
olasank [31]

Answer:

Part a: <em>Units of k is </em>M^{-2}s^{-1}<em> where reaction is first order in A and second order in B</em>

Part b: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is first order in A and second order overall.</em>

Part c: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is independent of the concentration of A and second order overall.</em>

Part d: <em>Units of k is </em>M^{-3}s^{-1}<em> where reaction reaction is second order in both A and B.</em>

Explanation:

As the reaction is given as

A+B \rightarrow C

where as the rate is given as

r=k[A]^x[B]^y

where x is the order wrt A and y is the order wrt B.

Part a:

x=1 and y=2 now the reaction rate equation is given as

r=k[A]^1[B]^2

Now the units are given as

r=k[A]^1[B]^2\\M/s =k[M]^1[M]^2\\M/s =k[M]^{1+2}\\M/s =k[M]^{3}\\M^{1-3}/s =k\\M^{-2}s^{-1} =k

The units of k is M^{-2}s^{-1}

Part b:

x=1 and o=2

x+y=o

1+y=2

y=2-1

y=1

Now the reaction rate equation is given as

r=k[A]^1[B]^1

Now the units are given as

r=k[A]^1[B]^1\\M/s =k[M]^1[M]^1\\M/s =k[M]^{1+1}\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part c:

x=0 and o=2

x+y=o

0+y=2

y=2

y=2

Now the reaction rate equation is given as

r=k[A]^0[B]^2

Now the units are given as

r=k[B]^2\\M/s =k[M]^2\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part d:

x=2 and y=2

Now the reaction rate equation is given as

r=k[A]^2[B]^2

Now the units are given as

r=k[A]^2[B]^2\\M/s =k[M]^2[M]^2\\M/s =k[M]^{2+2}\\M/s =k[M]^{4}\\M^{1-4}/s =k\\M^{-3}s^{-1} =k

The units of k is M^{-3}s^{-1}

7 0
3 years ago
Who turned the ragged Continental Army into a more efficient fighting force?
Goshia [24]
Von Steuben turned the ragged Continental Army into a more effective fighting force by drilling and teaching the army discipline
8 0
2 years ago
Select the correct answer.
Ilya [14]

Answer:

C is the answer hope I helped you have a good day by

3 0
3 years ago
Your amplifier is playing a 200 Hz tone. When you double the amplitude(loudness), what happens to the speed of the sound (v) and
kherson [118]
Its d. Speed (v) and frequency(f) both stay the same.

<span>Because Amplitude does not affect wave frequency. When you put more energy into the wave (larger amplitude) it does not affect how often you repeat a cycle. 
</span>Also speed can be altered when the medium changes through which it travels.
8 0
3 years ago
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