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gulaghasi [49]
3 years ago
9

A solution is made by dissolving 23.0 g KOH in 1.60 L H2O. What is the molality of the solution? The density of water is 1.00 g/

ml. Use the periodic table in the toolbar if needed.
Chemistry
2 answers:
Sophie [7]3 years ago
6 0
.256 is what it is on edgenuity
artcher [175]3 years ago
4 0
The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:

Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41

The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg

Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26

The molality of the solution is 0.26 molal.
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In the laboratory, a student dilutes 13.5 mL of a 11.6 M hydroiodic acid solution to a total volume of 100.0 mL. What is the con
igomit [66]

Answer: The concentration of the diluted solution is 1.566M.

Explanation:

The dilution equation is presented as this: M_{s} V_{s} =M_{d} V_{d}.

·M= molarity (labeled as M)

·V= volume (labeled as L)

·s= stock solution (what you started with)

·d= diluted solution (what you have after)

Now that we know what each part of the formula symbolizes, we can plug in our data.

11.6M*13.5mL=M_{d} *100mL

We cannot leave it like this because the volumes must be in Liters, not milliliters. To convert this, we divide the milliliters by 1000.

13.5mL/1000=0.0135L     100mL/1000=0.1L

Now that we have the conversions, let's plug them into the equation.

11.6M*0.0135L=M_{d} *0.1L

The only thing that we need to do now is actually solving the answer.

M_{d} =\frac{11.6M*0.0135L}{0.1L}       M_{d} =1.566M

From the work shown above, the answer is 1.566M.

I hope this helps!! Pls mark brainliest :)

7 0
1 year ago
A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has
natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

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goldfiish [28.3K]

Answer:

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Explanation:

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