A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
<h3>What is force?</h3>
The action of push or pull which changes the state of motion or rest of a body is called force.
The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.
The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.
F= (mv -mu) x t
The ball is initially at rest, so u =0
F = mvt
Substitute the values into the above equation of force to find the velocity.
v = F / mt
v =700 / (0.10 x 0.05)
v = 1.4 x 10⁵ m/s
Thus, the ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
Learn more about force.
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I only remember #9 sry. The answer is a plant cell
There is 1 Mg and 2 Cl i think
Refractive index of a medium = speed of light in vacuum
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speed of light in that medium
First, calculate the time it requires for the ball to reach the ground, given that its y-component is similar to that of the free-falling body through the equation,
d = 0.5gt²
Substituting the known values,
1.2 = 0.5(9.8 m/s²)(t²)
The value of t is equal to 1.56 seconds.
To calculate for the range of the given motion, we use the equation,
R = (Hx)t
where R is the range, Hx is the horizontal component of the force, and t is the time. Substituting,
R = (1.5 m/s)(1.56 s)
R = 2.34 m
Answer: 2.34 m