What the function would look like would be like this:
F = ma
F = 12n / 6.4 kg
= 1.9m/s^2
Hopefully this helped. :)
Answer:
m₃ = 30 kg
Explanation:
This is a problem of rotational equilibrium, let's write Newton's law for rotational equilibrium.
Let's fix our reference system in the support, the positive torques are those that create an anti-clockwise turn
Let's look for the distances to the point of support
The distance of man
x₁ = -3 m
The distance of the bar is
x₂ = L / 2 -3
x₂ = 10/2 -3
x₂ = 2 m
Remote object at the end
x₃ = L-3
x₃ = 10-3
x₃ = 7 m
They give us the mass of man (m1) and the mass of the bar (m2)
Let's write the torques
W₁ x₁ - W₂ x₂ - w₃ x₃ = 0
m₁ g 3 - m₂ g 2 - m₃ g 7 = 0
m₃ = (3m₁ -2m₂) / 7
Let's calculate
m₃ = (3 80 -2 15) / 7
m₃ = 30 kg
Answer:
Cause its scalar quantity
Explanation:
since speed does not take directions into consideration, it is considered to be a scalar quantity. On the other hand, the velocity of an object does not take into account direction, thus making it a vector quantity.
Answer:
The moment arm is 0.6 m
Explanation:
Given that,
First force 
Second force 
Distance r = 0.2 m
We need to calculate the moment arm
Using formula of torque
So, Here,
We know that,
The torque is the product of the force and distance.
Put the value of torque in the equation
Where, 
=First force
=First force
=Second force
= distance
Put the value into the formula
Hence, The moment arm is 0.6 m
