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IceJOKER [234]
3 years ago
5

Why is the direction of position V upwards?

Physics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

The wave is moving from left to right (as indicated by the arrow), so, given that at the current instance the amplitude of the position V is 0 (or whatever midpoint the dashed line corresponds to), in the immediately next instance the position will continue increasing as the wave moves from left to right. The peak currently shown at U will at some point "arrive" at V. At that point the location V will have the maximum amplitude. After that the direction at position will be downward, etc.

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Points a and b lie in a region where the y-component of the electric field is Ey=α+β/y2. The constants in this expression have t
Drupady [299]

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The electric potential is defined by

         V_{b} - V_{a} = - ∫ E .ds

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         V_{b} - V_{a} = - ∫ E ds

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We integrate

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           V_{b} - V_{a} = - α (0.03 - 0.02) + β (1 / 0.03 - 1 / 0.02)

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As they ask us the reverse case

             V_{b} - V_{a} = - V_{b} - V_{a}

             V_{a} - V_{b} = 89.3

3 0
3 years ago
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