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xxMikexx [17]
3 years ago
14

Compare your research question to the criteria provided. Which of the following statements describe your question? Check all of

the boxes that apply.
My question is an open-ended question.

I can’t easily predict the answer to the question.

The question extends beyond what I already know.

The question makes me curious.

Physics
2 answers:
MatroZZZ [7]3 years ago
6 0

The question extends beyond what I already know.

The question makes me curious.

SIZIF [17.4K]3 years ago
4 0

its me again i know but dont mind me i just want the brain

ehehhehehehehehehe

P.S MY FAV SONG IS

Why oh why can't you just fix me?

When all I want's to feel numb

But the medi/cation's all done

Why oh why does God hate me?

When all I want's to get high

And forget this so-called life

I am so frea/kin' bored

Nothin' to do today

I guess I'll sit around and medi/cate (med/icate)

I am so fre/akin' bored

Nothing to do today

I guess I'll sit around and med/icate (me/dicate)

Can't wait to feel better than I ever will

Attack that s/h/it like a kid on Bena/dryl

Chase it down with a hopeful smile

Hate myself, if I can go for miles

They say family's all you need

Someone to trust can help you breathe

Inhale that dr/ug, but you start to choke

You follow the outs of an inside joke

You might be interested in
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
rusak2 [61]

I'll bite:

-- Since the sled's mass is 'm', its weight is 'mg'.

-- Since the coefficient of kinetic friction is μk, the force acting opposite to the direction it's sliding is    (μk) times (mg) .

-- If the pulling force is constant 'F', then the horizontal forces on the sled
are 'F' forward and (μk · mg) backwards.

-- The net force on the sled is  (F - μk·mg).
(I regret the visual appearance that's beginning to emerge,
but let's forge onward.)

-- The sled's horizontal acceleration is  (net force) / (mass) = (F - μk·mg) / m.
This could be simplified, but let's not just yet.

-- Starting from rest, the sled moves a distance 's' during time 't'.
We know that  s = 1/2 a t² , and we know what 'a' is.  So we can write

           s = (1/2 t²)  (F - μk·mg) / m    .

Now we have the distance, and the constant force.
The total work is (Force x distance), and the power is (Work / time).
Let's put it together and see how ugly it becomes.  Maybe THEN
it can be simplified.

Work = (Force x distance) =  F x  (1/2 t²)  (F - μk·mg) / m
 
Power = (Work / time) =    <em>F (t/2) (F - μk·mg) / m </em>

Unless I can come up with something a lot simpler, that's the answer.


To simplify and beautify, make the partial fractions out of the
2nd parentheses:
                                   <em> F (t/2) (F/m - μk·m)</em>

I think that's about as far as you can go.  I tried some other presentations,
and didn't find anything that's much simpler.

Five points,ehhh ?


4 0
2 years ago
Read 2 more answers
Instead, suppose that it was fired upward at 60◦ with respect to a horizontal line. Then its horizontal component of velocity is
larisa [96]

Answer:

50 m/s

Explanation:

Angle = 60 degree

Horizontal component of velocity = 50 m/s

A projectile motion is the motion of an object in two dimensions under the influence of gravity.

In this case, the object has no acceleration along horizontal direction, it has acceleration in vertical direction which is equal to the acceleration due to gravity of earth.

When the projectile reaches at the maximum height it travels only along the horizontal and thus it has only horizontal velocity at that instant.

Thus, the velocity of teh projectile at maximum height is same as horizontal component of velocity that meas 50 m/s.

5 0
3 years ago
Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.4 × 10-4m2 and the speed of the water
Ksenya-84 [330]

To solve this problem it is necessary to apply the continuity equations in the fluid and the kinematic equation for the description of the displacement, velocity and acceleration.

By definition the movement of the Fluid under the terms of Speed, acceleration and displacement is,

v_2^2 = v_1^2 + 2gh

Where,

V_i = Velocity in each state

g= Gravity

h = Height

Our values are given as,

A_1 = 2.4*10^{-4} m^2

v_1 = 0.8 m/s

h = 0.11m

Replacing at the kinetic equation to find V_2 we have,

v_2 = \sqrt{v_1^2 + 2gh}

v_2 = \sqrt{(0.8 m/s)^2 + 2(9.80 m/s2)(0.11 m)}

v_2= 1.67 m/s

Applying the concepts of continuity,

A_1v_1 = A_2v_2

We need to find A_2 then,

A_2= \frac{A_1v_1 }{v_2}

So the cross sectional area of the water stream at a point 0.11 m below the faucet is

A_2= \frac{A_1v_1 }{v_2}

A_2= \frac{(2.4*10^{-4})(0.8)}{(1.67)}

A_2= 1.14*10^{-4} m2

Therefore the cross-sectional area of the water stream at a point 0.11 m below the faucet is 1.14*10^{-4} m2

8 0
3 years ago
If you put a object in front of the mirror why does it appear the opposite way
UNO [17]
It is because that is how mirrors work, they reflect light, and since we see objects because we are seeing the light these objects reflect, what is reflected back by the mirror is what we see.
4 0
3 years ago
The SI units for force are what?
arsen [322]

Answer:

The SI unit of force is Newton.

Explanation:

Newton is denoted by N.

Force can be defined as the pull or push which change or try to change the state of a body from motion to rest or rest to motion in a straight line.

6 0
3 years ago
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