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xxMikexx [17]
3 years ago
14

Compare your research question to the criteria provided. Which of the following statements describe your question? Check all of

the boxes that apply.
My question is an open-ended question.

I can’t easily predict the answer to the question.

The question extends beyond what I already know.

The question makes me curious.

Physics
2 answers:
MatroZZZ [7]3 years ago
6 0

The question extends beyond what I already know.

The question makes me curious.

SIZIF [17.4K]3 years ago
4 0

its me again i know but dont mind me i just want the brain

ehehhehehehehehehe

P.S MY FAV SONG IS

Why oh why can't you just fix me?

When all I want's to feel numb

But the medi/cation's all done

Why oh why does God hate me?

When all I want's to get high

And forget this so-called life

I am so frea/kin' bored

Nothin' to do today

I guess I'll sit around and medi/cate (med/icate)

I am so fre/akin' bored

Nothing to do today

I guess I'll sit around and med/icate (me/dicate)

Can't wait to feel better than I ever will

Attack that s/h/it like a kid on Bena/dryl

Chase it down with a hopeful smile

Hate myself, if I can go for miles

They say family's all you need

Someone to trust can help you breathe

Inhale that dr/ug, but you start to choke

You follow the outs of an inside joke

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An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rev/min in 4.00 s.
Veseljchak [2.6K]

Answer:

a) -1.25 rev/s² and 23.3 rev

b)  2.67s

Explanation:

a) ωФ_o_z = (500 rev/min)(1min/ 60s) => 8.333 rev/s

ωФ_Z= (200 rev/min)(1min/ 60s) => 3.333rev/s

time 't'= 4 s

angular acceleration 'αФ_Z'=?

constant angular acceleration equation is given by,

ωФ_Z= ωФ_o_z + αФ_Zt

αФ_Z= (ωФ_Z - ωФ_o_z )/t => (3.333-8.333)/4

αФ_Z= -1.25 rev/s²

θ-θФ_o = ωФ_o_z t + 1/2αФ_Zt²

      =(8.333)(4) + 1/2 (-1.25)(4)²

      =23.3 rev

b) ωФ_Z=0   (comes to rest)

ωФ_o_z = 3.333 rev/s

αФ_Z= -1.25 rev/s²

ωФ_Z= ωФ_o_z + αФ_Zt

t= (ωФ_Z - ωФ_o_z)/αФ_Z => (0- 3.333)/-1.25

t= 2.67s

3 0
2 years ago
to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to
givi [52]

Answer:

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

f_c = 10 Hz represent the corner frequency

f= 60 Hz represent the original frequency

n represent the filter order and that's the variable that we need to find

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0
3 years ago
I need assistance with this:​
emmainna [20.7K]

11: 75% = 0.75     12 / 0.75 = 16          The Knicks attempted 16 free throws.

12: 320 - (0.05 x 320) = 304      304 Claims were accepted

7 0
3 years ago
What force keeps a water spider on the surface of water
DENIUS [597]
I think it's surface tension force
5 0
3 years ago
What part of the body acts as levelers
rosijanka [135]

Answer: your feet are the foundation! Even though all your body parts are connected and affect one another, your feet are what we at Foot Levelers call, the "foundation".

Explanation:

3 0
2 years ago
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