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xxMikexx [17]
3 years ago
14

Compare your research question to the criteria provided. Which of the following statements describe your question? Check all of

the boxes that apply.
My question is an open-ended question.

I can’t easily predict the answer to the question.

The question extends beyond what I already know.

The question makes me curious.

Physics
2 answers:
MatroZZZ [7]3 years ago
6 0

The question extends beyond what I already know.

The question makes me curious.

SIZIF [17.4K]3 years ago
4 0

its me again i know but dont mind me i just want the brain

ehehhehehehehehehe

P.S MY FAV SONG IS

Why oh why can't you just fix me?

When all I want's to feel numb

But the medi/cation's all done

Why oh why does God hate me?

When all I want's to get high

And forget this so-called life

I am so frea/kin' bored

Nothin' to do today

I guess I'll sit around and medi/cate (med/icate)

I am so fre/akin' bored

Nothing to do today

I guess I'll sit around and med/icate (me/dicate)

Can't wait to feel better than I ever will

Attack that s/h/it like a kid on Bena/dryl

Chase it down with a hopeful smile

Hate myself, if I can go for miles

They say family's all you need

Someone to trust can help you breathe

Inhale that dr/ug, but you start to choke

You follow the outs of an inside joke

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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th
ipn [44]

Answer:

a) F_{fric} = 692 N

b) F_{applied} = 932 N

Explanation:

a)

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object  in all directions.

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

F_{applied} = 800 N

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F_{fric} = ?

800 - F_{fric} = (90)(1.2)

F_{fric} = 692 N

b)

According to newton's second law of motion,

F_{net}  ∝ a

F_{net} =  ma

F_{applied} - F_{fric} = ma

Given data:

If we assume the same friction and acceleration between player's feet and ground as calculated in part a

F_{fric} = 692 N

acceleration = a = 1.2 m/s²

We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.

Mass = M = m₁ + m₂ = 110 kg + 90 kg

= 200 kg

F_{applied} = ?

F_{applied} - 692 N = (200)(1.2)

F_{applied} = 692 + 240

F_{applied} = 932 N

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