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Dmitry_Shevchenko [17]
3 years ago
4

A rock (m= 2kg) is shot up vertically at the same time that a ball (m= 0.5kg) is projected horizontally. If both start from the

same height: A. the rock and ball will reach the ground at the same time.
B. the rock will reach the ground first.
C. the ball will reach the ground first.
D. the rock and ball will collide in the air before reaching the ground.
Can you explain why the answer is C?
Physics
1 answer:
Novosadov [1.4K]3 years ago
0 0

Answer:

The correct option is C. the ball will reach the ground first.

Explanation:

The ball will reach the ground first since the mass of each object does not affect the rate of fall, both are subject to the same gravitational acceleration 9.81 m / s2. The rock in its vertical movement invests a time that the ball is not released horizontally, so that time of vertical flight of the rock plus the extra height it will have will reach the ground after the rock. Regardless of the friction of the air, it will be different in both objects.

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A point charge q1=2.0μC is located on the positive y axis at y=0.30m, and an identical charge q2 is at the origin. Find the magn
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Answer:

(A) 0.279N at angle 38.02°

(B) 0.701N

(C) 14.19°

Explanation:

(A) The net force on q3 is given as:

F = Fxi + Fyj

Fx is the x component of the force

Fy is the y component of the force

Fx = -F(1, 3)cos(90 - x) + F(2, 3)cos0

Fy = -F(2, 3)cosx - F(2, 3)cos90 = -F(2, 3)cosx

First let us find y and angle x from the diagram.

Using Pythagoras theorem,

y² = 0.3² + 0.4²

y² = 0.25

y = 0.5m

Using SOHCAHTOA to find x,

sinx = 0.4/0.5

x = 53.13°

Electrostatic force, F is given as:

F = kqQ/r²

Where k = Coulumbs constant

F(1,3) = (k*q1*q3) / r²

F(1, 3) = (9 * 10^9 * 2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.5²)

F(1, 3) = 0.288N

F(2,3) = (k*q2*q3) / r²

F(2, 3) = (9 * 10^9 * 2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.4²)

F(2, 3) = 0.45N

Therefore,

Fx = -0.288cos36.87 + 0.45

Fx = 0.22N

Fy = 0.288cos53.13

Fy = 0.172N

=> F = 0.22i + 0.172j

The magnitude of the force will be

F(mag) = √(0.22² + 0.172²)

F(mag) = 0.279N

The direction of the force makes will be

tanθ = Fy/Fx

tanθ = 0.172/0.22 = 0.781

θ = 38.02° to the x axis.

(B) q2 = - 2.0 * 10^(-6)

This implies that:

F(2,3) = (k*q2*q3) / r²

F(2, 3) = (9 * 10^9 * -2.0 * 10^(-6) * 4.0 * 10^(-6)) / (0.4²)

F(2, 3) = -0.45N

Therefore,

Fx = -0.288cos36.87 - 0.45

Fx = -0.68N

Fy = 0.172N

=> F = - 0.68i + 0.172j

The magnitude of the force will be

F(mag) = √((-0.68)² + 0.172²)

F(mag) = 0.701N

(C) The direction of the force makes will be

tanθ = 0.172/0.68

θ = 14.19° to the x axis

4 0
3 years ago
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What kind of lens is there in our eyes? where does it form the image of an object?​
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Answer:

convex lens

Explanation:

An image is form in retina with light rays converging most at cornea and upon entering and existing the lens.Rays from top and bottom of the object are traced and produce an inverted image on the retina

8 0
2 years ago
A vehicle moving with a uniform acceleration of 2 m/s2 has
Dahasolnce [82]

Answer:

a) 6 m/s

b) 14 m/s

Explanation:

Acceleration is change in velocity over change in time.

a) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 1 s

v = 6 m/s

b) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 5 s

v = 14 m/s

6 0
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Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the frequency of radio wave radiation that h
Archy [21]

Answer:

The frequency of the radio wave is 328587Hz

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensities, that radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

Radiation is distributed along that electromagnetic spectrum according with the wavelength or frequency. For example, X-rays, ultraviolet rays, the visible region are the ones with the highest frequencies and infrared, microwave and radio waves with lower frequencies.

Light propagates as electromagnetic wave in vacuum with a speed of 3x10^{8}m/s. Therefore, radio waves will have in vacuum the same speed.

Therefore, in order to know the frequency the following equation can be used:

c = \nu \cdot \lambda  (1)

\nu = \frac{c}{\lambda}  (2)

Where \nu is the frequency, c is the speed of light and \lambda is the wavelength.

\nu = \frac{3x10^{8}m/s}{913m}

\nu = 328587s^{-1}

\nu = 328587Hz

Hence, the frequency of the radio wave is 328587Hz.

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3 years ago
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D. The farther away a galaxy is, the faster moving it is moving
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