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3 years ago

The skillful and effective interaction of movements; completing more than one movement at a time

Physics

2 answers:

horrorfan [7]3 years ago

7 0

It is called balance

prisoha [69]3 years ago

4 0

It’s definitely balance :)

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The moon does not stay at the same distance from the earth.why?

Artist 52 [7]

Answer:

The moon does not stay at the same distance of the earth because the ortbit of the moon is slightly elliptical. If earth is not tilted at an angle of 66.5°, there will be no change in the season and the earth will have equal length of days and night.

Explanation:

mark me brainlest

5 0

3 years ago

What is the maximum mass that can hang without sinking from a 20-cm diameter Styrofoam sphere in water? Assume the volume of the

alex41 [277]

Answer:

the maximum mass that can hang without sinking is 2.93 kg

Explanation:

Given: details:

sphere diameter d = 20 cm

so, radius r = 10 cm = 0.10 m

density of the Styrofoam sphere D = 300 kg/m3

sphere volume $V = \frac{4}{3} \pi r^3$

$=\frac{4}{3} \pi 0.10^3$

=4.18*10^{-3} m^3

we know that

$Density = \frac{Mass}{Volume}$

mass M = Density * Volume

= (300)(4.18*10^{-3} m3)

=1.25 kg

mass of the water displace = volume *density of water

= 4.18*10^{-3} m3 * 1000

= 4.18 kg

The difference between the mass of water and mass of styrofoam is the amount of mass that the sphere can support

=4.18 kg -1.25 kg

= 2.93 kg

3 0

4 years ago

A 190-N box is placed on an inclined plane that makes a 20.0° angle with the horizontal. Find the component of the weight force

andrey2020 [161]

Explanation:

190-N divided by 20.0 is definitely 9.5 for the component of the weight force parallel to the planes surface

4 0

3 years ago

Car A rear ends Car B, which has twice the mass of A, on an icy road at a speed low enough so that the collision is essentially

puteri [66]

Answer:

Vb = v/2

Half of the speed of Car A before the collision

Explanation:

This problem can be solved by using conservation of momentum.

$m_{A}*v_{A1} + m_{B}*v_{B1} = m_{A}*v_{A2} + m_{B}*v_{B2}$

Since car B was stopped before the collision and its mass is twice the mass of A:

$v_{B1} = 0\\m_{B} = 2*m_{A}$

Also, since it is an elastic collision, car A stops after hitting car B. Rewriting the equation:

$m_{A}*v_{A1} + 2m_{A}*0 = m_{A}*0 + 2m_{A}*v_{B2}\\m_{A}*v_{A1} = 2m_{A}*v_{B2}\\v_{B2}=\frac{v_{A1}}{2}$

Therefore, the speed of car B after the collision is half of the speed of car A before the collision (v)

Vb = v/2

8 0

4 years ago

After robbing a bank, a criminal tries to escape from the police by driving at a constant speed of 55 m/s (about 125 mph). A pol

vfiekz [6]

Answer:

18.03 s

Explanation:

We have two different types of motions, the criminal moves with uniform motion while the police do it with uniformly accelerated motion. Therefore we will use the equations of these cases. We know that by the time the police reach the criminal they will have traveled the same distance.

$x=vt\\x=x_{0}+v_{0}t+\frac{a}{2}t^2$

The distance between the police and the criminal when the first one starts the persecution is 0, its initial speed is also zero. So:

$x=(55m/s)t\\x=\frac{6.1m/s^2}{2}t^2=(3.05m/s^2)t^2$

Equalizing these two equations and solving for t:

$(55m/s)t=(3.05m/s^2)t^2\\(3.05m/s^2)t^2-(55m/s)t=0\\t((3.05m/s^2)t-55m/s)=0\\t=0 \\(3.05m/s^2)t-55m/s=0\\t=\frac{55m/s}{3.05m/s^2}=18.03 s$

6 0

3 years ago