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antoniya [11.8K]
3 years ago
10

What is the poH of a 4.8 x 10-10 M H+ solution?

Chemistry
1 answer:
stiks02 [169]3 years ago
6 0

Answer: pOH = 4.68

Explanation:

pOH = 14 - pH

pH = - Log [H+]

= - Log [4.8 x 10^-10]

= -(-9.32)

pH =+9.32

Therefore, pOH= 14 - 9.32

= 4.68

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How does a sample of hydrogen at 10 degrees Celsius compare to a sample of hydrogen at 350K?
Sophie [7]

Answer:

We can compare the both sample by taking into account the kinetic energy.

By increasing the temperature kinetic energy of gas molecules increased.

Explanation:

It is known that kinetic energy of molecules is increased by increasing the temperature.

We are given with two sample of hydrogen one is at 10°C and other is at 350 K.

Hydrogen sample at 10°C = 273.15 + 10 = 283.15 k

Thus one sample is at 283.15 K and other is at 350 K. So, the sample at higher temperature i.e 350 K will have more kinetic energy of molecules.

While the sample at 283.15 K will have less speed of molecule and kinetic energy.

8 0
3 years ago
Phase change involves changing states of matter (solid-liquid-gas). How do these three states of matter differ from each other?
Morgarella [4.7K]

solid : the molecules are tightly packed

liquid : the molecules have some space in them

gas : molecules can freely move around

4 0
2 years ago
A beaker contains 500 ml of 2.40M KNO3 the beaker is left uncovered so that all of the water evaporates. What mass of KNO3 cryst
telo118 [61]

Answer:

242.4 g

Explanation:

RAM of KNO3=39+14+(16×3)=101

Mass=morality×RAM

101*2.4=242.4

6 0
3 years ago
Octane (C8H18) is a component of gasoline that burns
MatroZZZ [7]

Answer:

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Explanation:

4 0
3 years ago
For the reaction, Cl2 + 2KBr --> 2KCl + Br2, how many moles of potassium chloride, KCl, are produced from 102g of potassium b
Sedaia [141]

Solution :

From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .

Moles of KBr in 102 g of potassium bromide.

n = 102/119.002

n = 0.86 mole.

So, number of miles of KCl produced are also 0.86 mole.

Mass of KCl produced :

m = 0.86 \times Molar \  mass \ of \  KCl\\\\m = 0.86 \times 74.5 \ gram \\\\m = 64.07\  gram

Hence, this is the required solution.

5 0
3 years ago
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