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3 years ago

How do geologists use seismic waves to locate an earthquakes epicenter

Chemistry

1 answer:

GREYUIT [131]3 years ago

6 0

The waves detect magnetic waves and the disturbances in the to locate where a earth quake will or may hit

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Which statement best describes the oxidation numbers of the atoms found in magnesium chloride? A. Magnesium has a 2- oxidation n

In-s [12.5K]

B. is the correct answer of your question

6 0

3 years ago

Read 2 more answers

NEED HELP FAST!!

koban [17]

Answer:

I'm pretty sure that's right.

Explanation:

Download pdf

8 0

3 years ago

When 3.51 g of phosphorus was burned in chlorine, the product was a phosphorus chloride. Its vapor took 1.77 times as long to ef

kumpel [21]

Answer:

molar mass of the phosphorus chloride = 138.06 g/mol

Explanation:

mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.

mass = 3.51 g

lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec

From this we can say that

rate of effusion of CO2 = 3.51/1 = 3.51 g/s

rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s

From graham's equation of effusion,

$\frac{Rc}{Rp}$ = $\sqrt{\frac{Mp\\}{Mc} }$

Rc = rate of effusion of CO2 = 3.51 g/s

Rp = rate of effusion of phosphorus chloride = 1.98 g/s

Mc = molar mass of CO2 = 44.01 g/mol

Mp = molar mass of the phosphorus chloride = ?

Imputing values into the equation, we have

$\frac{3.51}{1.98}$ = $\sqrt{\frac{Mp\\}{44.01} }$

1.77 = $\frac{\sqrt{Mp} }{6.64}$

11.75 = $\sqrt{Mp}$

Mp = $11.75^{2}$

Mp = molar mass of the phosphorus chloride = 138.06 g/mol

5 0

3 years ago

The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof

sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O ⇄ H₃O⁺ + F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the [ H₃O⁺ ] ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1 relation , we will also have [F⁻ ]. The [ HF ] is given in the question so we have all the information that is needed to compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻² M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴

(Rounded to two significant figures, the powers of 10 have infinite precision )

4 0

3 years ago

The compound responsible for the characteristic smell of garlic is allicin, c6h10os2. the mass of 1.00 mol of allicin, rounded t

Gemiola [76]

The compound responsible for the characteristic smell of garlic is allicin, that is having molecular formula C₆H₁₀OS₂.

Molar mass of C₆H₁₀OS₂=162.26 g mol⁻¹.

number of moles of C₆H₁₀OS₂=1 mol

So mass of C₆H₁₀OS₂ can be calculated as:

$Number of moles of C_{6}H_{10}OS_{2}, n= \frac{Given mass of the }{Molar mass of theC_{6}H_{10}OS_{2}}$

$1= \frac{Given mass of the C_{6}H_{10}OS_{2}}{162.26}$

Given mass of the C₆H₁₀OS₂= 162 g

4 0

3 years ago