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4 years ago

How will the frequency of a wave appear to change if the source of the wave is moving toward an observer

Physics

2 answers:

amm18124 years ago

6 0

pitch goes up on approach ... Doppler effect

ad-work [718]4 years ago

5 0

Frequency would increase I think...

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a 1811kg car speeds up from rest when a traffic light turns green until it reaches a speed of 23m/s. how much work was done on t

sattari [20]

Answer:

The work done by the frictional force, W = 612565.32 J

Explanation:

Given data,

The mass of the car, m = 1811 kg

The initial velocity of the car, u = 0 m/s

The final velocity of the car, v = 23 m/s

Let the time period of the car be, t = 3 s

The acceleration of the car,

a = (v-u) /t

= (23 - 0)/ 3

= 7.67 m/s²

The normal force acting on the car,

F = mg

= 1811 kg x 9.8 m/s²

= 17747.8 N

The displacement of the car,

s = ut + ½ at²

= 0 + ½ x 7.67 x 3²

= 54.52 m

The work done by the frictional force,

W = F · S

W = 17747.8 N x 54.52 m

= 612565.32 J

Hence, the work done by the frictional force, W = 612565.32 J

3 0

3 years ago

Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart

Anna71 [15]

If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.

3 0

3 years ago

Read 2 more answers

What happens to force when pressure is doubled?

san4es73 [151]

When the force on some area is doubled and the area doesn't change,
then the pressure on that area has doubled.

7 0

3 years ago

Read 2 more answers

Which of the following is equivalent to 4.5 m?

Romashka [77]

We can’t see the following

3 0

3 years ago

A rectangular sharp-crested weir is contracted on both sides, and the opening is 1.2 m wide. At what height (Hw) should it be pl

Alex

Answer:

H_w = 2.129 m

Explanation:

given,

Width of the weir, B = 1.2 m

Depth of the upstream weir, y = 2.5 m

Discharge, Q = 0.5 m³/s

Weir coefficient, C_w = 1.84 m

Now, calculating the water head over the weir

$Q = C_w BH^{3/2}$

$H = (\dfrac{Q}{C_wB})^{2/3}$

$H = (\dfrac{0.5}{1.84\times 1.2})^{2/3}$

$H = 0.371\ m$

now, level of weir on the channel

H_w = y - H

H_w = 2.5 - 0.371

H_w = 2.129 m

Height at which weir should place is equal to 2.129 m.

7 0

4 years ago